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3 years ago

Atom with the largest atomic radius in group 18

Chemistry

1 answer:

Mkey [24]3 years ago

8 0

Answer:

Radon

Explanation:

Group eighteen elements are called noble gases. This group includes helium, neon, argon, krypton, xenon and radon.

Radon is present at the last of this column.

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

Thus radon has largest atomic radius.

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How many significant digits are in the measurement 64,000 mg<br> A.2 <br> B.3<br> C.4<br> D.5

Y_Kistochka [10]

5 because the 0's all matter.

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3 years ago

f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a

Eduardwww [97]

Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of 0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is 0.157M</h3>

7 0

3 years ago

Read 2 more answers

A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v

hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

= (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

= (-75000 J) - ( -13071 J)

= -75000 J + 13071 J

= -61929 J

Total energy change, ΔE = -61.929 kJ

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3 years ago

Using the symbol below/above determine the number of protons, neutrons, and electrons in the element.

malfutka [58]

Hi,
The correct answer is C.
Protons= 50 (because the atomic number of Sn is 50) —> The atomic number always represent the number of protons

Neutrons= 68 (if you want to find the number of neutrons, you need to do: atomic mass (118 in this case) - your number of protons (50)

Electrons= 46 (50 - 4)

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3 years ago

The<br> is an organ that supplies blood and nutrients to a<br> developing embryo.

statuscvo [17]

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Explanation:-

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3 years ago