Answer:
<h2>15.37 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>15.37 moles</h3>
Hope this helps you
Answer:
The percent composition for nitrogen in chromium(III) nitrate is 6%.
Explanation:
Answer:
C₂ = 0.149 M
Explanation:
Given data:
Initial concentration = 0.407 M
Initial volume = 2.56 L
Final volume = 7.005 L
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ =Final volume
Now we will put the values.
0.407 M × 2.56 L = C₂ × 7.005 L
1.042 = C₂ × 7.005 L
C₂ = 1.042 M.L / 7.005 L
C₂ = 0.149 M
Enyzmes speed up all chemical reactions
(Just took an AP Bio test with this question on it)
Answer:
0.2349 moles, 10.3356 g
Explanation:
The given reaction is :

The balanced reaction by equating the same number of each atom both side is :

Given that :
Amount of oxygen gas = 11.9 g
Molar mass of oxygen gas = 32 g/mol
The formula for the calculation of moles is shown below:
Thus, moles are:
From the reaction,
19 moles of oxygen gas on reaction forms 12 moles of carbon dioxide
Also,
1 mole of oxygen gas on reaction forms 12/19 moles of carbon dioxide
So,
0.3719 moles of zinc on reaction forms
mole of carbon dioxide
<u>Moles of carbon dioxide formed = 0.2349 moles</u>
Mass of carbon dioxide = moles×Molar mass
Molar mass of carbon dioxide = 44 g/mol
<u>Mass of carbon dioxide formed = 0.2349 ×44 g = 10.3356 g</u>