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Hoochie [10]
2 years ago
15

How many g are equal to 345.7mg?

Chemistry
2 answers:
Finger [1]2 years ago
5 0
The answer is 0.3457g equal to 345.7mg
Mumz [18]2 years ago
4 0

Answer:

0,3457 grams equal to 345.7mg

Explanation:

1000 mg-------1 g

345.7mg------x= (345.7mgx 1 g)/1000mg= <em>0,3457 g</em>

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Carbon atoms can be identified based on the # of which subatomic particles
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And in addition if we know the number of neutrons we can easily find out the atomic mass of an element because

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2 years ago
Explain how cells use digested food in your own words
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Answer:

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3 0
3 years ago
Breeder reactors are used to convert the nonfissionable nuclide U-238 to a fissionable product. Neutron capture by the U-238 is
m_a_m_a [10]

Answer:

Pu-239

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It takes to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond
Zolol [24]

The given question is incomplete. The complete question is :

It takes 151 kJ/mol to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon. Be sure your answer has the correct number of significant digits.

Answer:  793 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = 151 kJ= 151000 J   (1kJ=1000J)

N= moles = 1 = 6.023\times 10^{23}

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light  = 3\times 10^8m/s

\lambda = wavelength of light  = ?

Putting in the values:

151000J=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{\lambda}

{\lambda}=7.93\times 10^{-7}m=793nm    1m=10^{-9}nm

Thus  the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon is 793 nm

3 0
2 years ago
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