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Hoochie [10]
2 years ago
15

How many g are equal to 345.7mg?

Chemistry
2 answers:
Finger [1]2 years ago
5 0
The answer is 0.3457g equal to 345.7mg
Mumz [18]2 years ago
4 0

Answer:

0,3457 grams equal to 345.7mg

Explanation:

1000 mg-------1 g

345.7mg------x= (345.7mgx 1 g)/1000mg= <em>0,3457 g</em>

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When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be
Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

        AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

                    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                     0.269 M = \frac{\text{no. of moles}}{1.14 L}

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                   0.307 mol = \frac{mass}{143.32 g/mol}

                           mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

                 

8 0
2 years ago
In a normal cellular protein, where would you expect to find a hydrophobic amino acid like valine?
Irina-Kira [14]
In a branched chain of amino acids
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What do the molecules do when they gain more kinetic energy and how does that affect the density?
GREYUIT [131]

The more kinetic energy a substance has, the warmer it will be and the faster particles will be moving, which reduces the density of the substance

3 0
3 years ago
Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
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Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0
3 years ago
Read the given chemical reaction.
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