The building with incandescent light bulbs would have higher energy bills because less than 10% of the bulb is used for light while the rest is given off as heat. Fluorescent light bulbs use ¼ as much energy and provide the same amount of light.
Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, 
Taking antilog both side, we get :

Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :

Hence, this is the required solution.
Answer:
Mass of carbon dioxide = 7.48 g
Explanation:
Given data:
Mass of lithium carbonate = 12.5 g
Mass of carbon dioxide produced = ?
Solution:
Chemical equation:
Li₂CO₃ → Li₂O + CO₂
Number of moles of Li₂CO₃:
Number of moles = mass/ molar mass
Number of moles = 12.5 g /73.89 g/mol
Number of moles = 0.17 mol
Now we will compare the moles of Li₂CO₃ with CO₂.
Li₂CO₃ : CO₂
1 : 1
0.17 : 0.17
Mass of carbon dioxide:
Mass of carbon dioxide = number of moles × molar mass
Mass of carbon dioxide = 0.17 mol × 44 g/mol
Mass of carbon dioxide = 7.48 g
Answer:

Explanation:
The molecular mass of a monomer unit is:
C₂H₃Cl = 2×12.01 + 3×1.008 + 35.45 = 24.02 + 3.024 + 35.45 = 62.494 u
For 1565 units,
