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4 years ago

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In Part A, you found the amount of product (2.60 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Par

t B, you found the amount of product (2.20 mol P2O5 ) formed from the given amount of oxygen and excess phosphorus.Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.Express your answer to three significant figures and include the appropriate units.

1 answer:

m_a_m_a [10]4 years ago

3 0

Explanation:

Equation of the reaction:

P₄ + 5O₂ → 2P₂O₅.

Given:

Mass of P₄ = 161 g.

Molar mass = 124 g/mol

Number of moles of P₄ = mass/molar mass

n(P₄) = 161 g ÷ 124 g/mol.

= 1.3 mol.

Mass of O₂ = 176 g.

Molar mass of O₂ = 2 ×16

= 32 g/mol

Number of moles = 176 g ÷ 32 g/mol.

= 5.5 moles

Calculating the limiting reactant,

5.5 mol of O2/5 mole of O2 × 1 mole of P₄

= 2.75 moles of P₄ (> 1.3 moles)

P₄ is the limiting reagent.

By stoichiometry, 1 mole of P₄ gives 2 mole of P₂O₅

Therefore, number of moles of P₂O₅ = 2 × 1.3

= 2.6 moles of P₂O₅ was formed.

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A 250 cm^3 solution containing 1,46 g of sodium chloride is added to an excess of silver nitrate solution. The reaction is given

faust18 [17]

Answer:

The mass of the precipitate that AgCl is 3.5803 g.

Explanation:

a) To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (NaCl) = 1.46 g

Molar mass of sulfuric acid = 58.5 g/mol

Volume of solution = $250 cm^3 =250 mL$

$1 cm^3= 1 ml$

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.46g\times 1000}{58.5g/mol\times 250}\\\\\text{Molarity of solution}=0.09982 M$

0.09982 M is the concentration of the sodium chloride solution.

b) $NaCl (aq)+AgNO_3 (aq)\rightarrow AgCI(s)+NaNO_3(aq)$

Moles of NaCl = $\frac{1.46 g}{58.5 g/mol}=0.02495 mol$

according to reaction 1 mol of NaCl gives 1 mol of AgCl.

Then 0.02495 moles of NaCl will give:

$\frac{1}{1}\times 0.02495 mol=0.02495 mol$ of AgCl

Mass of 0.02495 moles of AgCl:

$0.02495 mol\times 143.5 g/mol=3.5803 g$

The mass of the precipitate that AgCl is 3.5803 g.

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3 years ago

"An aqueous CaCl2 solution has a vapor pressure of 83.1mmHg at 50 ∘C. The vapor pressure of pure water at this temperature is 92

Lynna [10]

Answer : The the concentration of $CaCl_2$ in mass percent is, 41.18 %

Solution : Given,

Molar mass of water = 18 g/mole

Molar mass of $CaCl_2$ = 110.98 g/mole

First we have to calculate the mole fraction of solute.

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

$\fac{p^o-p_s}{p^o}=X_B$

where,

$p^o$ = vapor pressure of the pure component (water) = 92.6 mmHg

$p_s$ = vapor pressure of the solution = 83.1 mmHg

$X_B$ = mole fraction of solute, $(CaCl_2)$

Now put all the given values in this formula, we get the mole fraction of solute.

$\fac{92.6-83.1}{92.6}=X_B$

$X_B=0.102$

Now we have to calculate the mole fraction of solvent (water).

As we know that,

$X_A+X_B=1\\\\X_A=1-X_B\\\\X_A=1-0.102\\\\X_A=0.898$

The number of moles of solute and solvent will be, 0.102 and 0.898 moles respectively.

Now we have to calculate the mass of solute, $(CaCl_2)$ and solvent, $(H_2O)$ .

$\text{Mass of }CaCl_2=\text{Moles of }CaCl_2\times \text{Molar mass of }CaCl_2$

$\text{Mass of }CaCl_2=(0.102mole)\times (110.98g/mole)=11.32g$

$\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O$

$\text{Mass of }H_2O=(0.898mole)\times (18g/mole)=16.164g$

Mass of solution = Mass of solute + Mass of solvent

Mass of solution = 11.32 + 16.164 = 27.484 g

Now we have to calculate the mass percent of $CaCl_2$

$Mass\%=\frac{\text{Mass of}CaCl_2}{\text{Mass of solution}}\times 100=\frac{11.32g}{27.484g}\times 100=41.18\%$

Therefore, the the concentration of $CaCl_2$ in mass percent is, 41.18 %

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Priscilla was building a circuit that used copper wires to connect a battery to a light bulb. As she connected the final wire fr

algol [13]

Answer:

The voltage or potential difference

Explanation:

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This force is supplied by the battery or the mains electrical circuit.

Every circuit requires the voltage to drive current through
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katovenus [111]

Answer:

An electron is a negatively charged subatomic particle and a proton is a positively charged subatomic particle. Positive charge(s) attract negative charge(s) and vice versa. The proton and neutron stay together and attract one another to give the atom an overall charge of zero (neutral). Which is the charge of an atom. When there is an unequal number of protons and neutrons an ion is formed. If the number of protons are more than the electron, a positively charged ion called cation is formed. On the other hand, if the number of electrons are more than the protons a negatively charged ion called anion is formed.

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dalvyx [7]

Answer:

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Explanation:

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