Answer:
2x2+9x−1=x
Step 1: Subtract x from both sides.
2x2+9x−1−x=x−x
2x2+8x−1=0
Step 2: Use quadratic formula with a=2, b=8, c=-1.
x=
−b±√b2−4ac
2a
x=
−(8)±√(8)2−4(2)(−1)
2(2)
x=
−8±√72
4
x=−2+
3
2
√2 or x=−2+
−3
2
√2
Step-by-step explanation:
This is what I got but I'm not 100% positive. I checked it on a calculator and it seemed to check out.
The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...
The mean is centered among the other numbers in both sets of data.
_____
The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
Answer:
The towel bar should be placed at a distance of
from each edge of the door.
Step-by-step explanation:
Given:
Length of the towel bar = 
Now given length is in mixed fraction we will convert in fraction.
To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.
can be Rewritten as 
Length of the towel bar = 
Length of the door = 
can be Rewritten as 
Length of the door = 
We need to find the distance bar should be place at from each edge of the door.
Solution:
Let the distance of bar from each edge of the door be 'x'.
So as we placed the towel bar in the center of the door it divides into two i.e. '2x'
Now we can say that;

Now we will take LCM to make the denominators common we get;

Now denominators are common so we will solve the numerators.

Or 
Hence The towel bar should be placed at a distance of
from each edge of the door.
Answer:
the probability is 2/5
Step-by-step explanation:
just put 8 over 20 and simplify it