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givi [52]
2 years ago
13

How many parties must be involved in an externality? Identify them.

Social Studies
1 answer:
son4ous [18]2 years ago
4 0

Answer:

hey do u have snap or insta ? you look hot

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Sue goes to a movie with her friends. Her phone starts ringing during the movie and she is aware that this is quite distracting
damaskus [11]

Answer:

I believe the answer is B

Explanation:

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3 years ago
True or False: In general, term loans can be created more quickly than bond issues because they (1) tend to be negotiated direct
kaheart [24]

Answer: True Option b

Explanation: the

disclosure and regulatory needs in effecting a public bond issue are taskingly difficult and stressful due to it different procedures.loan documentation does not usually takes time. Some can be a day and maximum is3-6 days but in bonds, it quite different, it takes week to document and finalize. At most 3 weeks upward.

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3 years ago
Read 2 more answers
Principles of internal control include all of the following except: Multiple Choice Perform regular and independent reviews. Mai
pishuonlain [190]

<u>Principle of internal control </u>does not include application of technological controls

Explanation:

<u>The seven important  internal control procedures include  separation/segregation  of duties/job responsibilities , providing access to various controls, performing physical audits, standardization of  documents, trial balances, periodic reconciliations of the financial statements , and approval authority.</u>

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3 years ago
Why do you think that colonists living in New
Gala2k [10]
During that time period it was before the Enlightenment. Which meant that people could no prove many of the things happening in the world. They were also subject to nature when living in The New World and not to mention most colonies up in the New England area moved there for religious freedom.
6 0
2 years ago
3.6.46-T Consider the following sample data for two variables. x 7 8 5 3 9 y 7 5 9 7 7 a. Calculate the sample covariance. b. Ca
Mrac [35]

Answer:

1. Co-variance= -1.2

2. correlation coefficient= -0.4404

3.  There is weak negative relationship between x and y.

Explanation:

1.

Co-variance= Cov(x,y)= sum[(x-xbar)(y-ybar)]/n

xbar=sumx/n=32/5=6.4

ybar=sumy/n=35/5=7

x 7 8 5 3 9

x-xbar 0.6 1.6 -1.4 -3.4 2.6

y 7 5 9 7 7

y-ybar 0 -2 2 0 0

(x-xbar)(y-ybar) 0 -3.2 -2.8 0 0

Cov(x,y)= sum[(x-xbar)(y-ybar)]/n=-6/5=-1.2

Cov(x,y)=-1.2

2.

correlation coefficient=r

r=\frac{sum(x-xbar)(y-ybar)}{\sqrt{sum(x-xbar)^2sum(y-ybar)^2} }

x 7 8 5 3 9

x-xbar 0.6 1.6 -1.4 -3.4 2.6

y 7 5 9 7 7

y-ybar 0 -2 2 0 0

(x-xbar)(y-ybar) 0 -3.2 -2.8 0 0

(x-xbar)² 0.36 2.56 1.96 11.56 6.76

(y-ybar)²  0 4 4 0 0

r=\frac{-6}{\sqrt{23.2(8)} }

r=-0.4404

3. Since the value of correlation coefficient is negative and less than 0.5 , so, we can say that there is weak negative relationship between x and y.

7 0
3 years ago
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