Let's say x is longest side, y is shortest side and z is the other side. So we have some equations such that
(by the first sentence)
(by the second sentence)
(by the third sentence)
By the second equation, we have
and if we use it in the first equation, then
. So
Since
, if we use it in the third equation the we have
then
Therefore
Answer: It is 1/12
Step-by-step explanation:
There are a total of 12 cards. If you look at the table, there is only one yellow card that is even. So it is 1/12.
Answer:
B
Step-by-step explanation:
Givens
a^2 + b^2 = c^2
a = 4x
b = x + 2
c = 3x + 4
Solution
(4x)^2 + (x + 2)^2 = (3x + 4)^3 Remove all the brackets.
16x^2 + x^2 + 4x + 4 = 9x^2 + 24x + 16 Collect like terms on the left
17x^2 + 4x + 4 = 9x^2 + 24x + 16 Subtract the terms on the right
8x^2 - 20x - 12 = 0
This factors into
(4x - 12)(2x + 1)
There are 2 answers
4x - 12 = 0
4x = 12
x = 12/4
x = 3
or
2x + 1 = 0
2x = - 1
x = - 1/2
You have to look at x = -1/2 carefully. The problem is that 4x = 4*(-1/2) = - 2 which is not possible in Euclidean Geometry.
So the only answer is x = 3
The answer is B)x+y=y+x.
This is just changing the order of the numbers to get the same equation....\
So for example if I have 2+7 and I use the property of addition It would give me 2+7=7+2.
Pls mark brainliest if this helped!
