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baherus [9]
3 years ago
11

I need to submit my homework in an hour, this is only question i cant solve. someone pls help!!

Physics
1 answer:
Sauron [17]3 years ago
8 0

Hope this helps.......☺

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two horses pull against a rope with forces of 100 newtons in opposite directions. this is an example of
statuscvo [17]
It is an example of balanced force.


hope this helps. good luck 
4 0
3 years ago
Read 2 more answers
Name the material used to transfer of charges from one body to other​
Evgesh-ka [11]

Answer:

conductor

Explanation:

A "conductor" is a material that allows the charges to pass freely from one body to the other. This causes a movement among the electrons and this means that<em> the charge will be passed entirely to the object receiving it.</em> This is also called <em>"conductive material."</em>

Examples of conductors are: <em>copper, aluminum, gold, silver, seawater, etc.</em>

The opposite of conductors are called "insulators." These do not allow the free movement of charges from one object to the other.

Examples of insulators: <em>plastic, rubber, paper, glass, wool, dry air, etc.</em>

6 0
3 years ago
If one of two interacting charges is doubled, the force between the charges will _____________.
malfutka [58]

If one of two interacting charges is doubled, the force between the charges will double.

Explanation:

The force between two charges is given by Coulomb's law

F=\frac{k q1 q2}{r^{2}}

K=constant= 9 x 10⁹ N m²/C²

q1= charge on first particle

q2= charge on second particle

r= distance between the two charges

Now if the first charge is doubled,

we get F'=\frac{k (2q1) q2}{r^{2}}

F'= 2 F

Thus the force gets doubled.

4 0
3 years ago
Hey can anyone help me out in dis pls!
patriot [66]

Answer:

D

Explanation:

3 0
3 years ago
Read 2 more answers
Two cars are traveling along perpendicular roads, car A at 40 mi/hr, car B at 60 mi/hr. At noon, when car A reaches the intersec
Serggg [28]

Answer:

\frac{dD}{dt} = -4 miles/hour

negative sign indicates that the distance is decreasing with time

Explanation:

Let at any time t after noon that is 12 p.m.  

distance traveled by car A = 40t

distance traveled by car B = 90-60t

then distance between the two cars at time t

D^2= (40t)^2+(90-60t)^2............1

also, at time 1 p.m.

distance D^2= (40\times1)^2+(90-60\times1)^2

D=50 Km

differentiating equation 1 w.r.t. t we get

2D\frac{dD}{dt}= 2\times40t\times40+2(90-60t)(-60)

put t= 1 and D= 50 we get

2\times50\frac{dD}{dt}= 3200\times1-3600\times1

\frac{dD}{dt} = -4 miles/hour

3 0
3 years ago
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