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baherus [9]
3 years ago
11

I need to submit my homework in an hour, this is only question i cant solve. someone pls help!!

Physics
1 answer:
Sauron [17]3 years ago
8 0

Hope this helps.......☺

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Where is the planet moving faster?
valentinak56 [21]

Answer:

I looked it up but got perihelion so I don't know if that will help at all but try um.... I don't know try L

Explanation:

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2 years ago
Why is it warmer near the equator and cooler near the poles?
Phantasy [73]
It is because the equator is closer to the sun and because the sun's rays hit the surface of the Earth at a higher angle at the equator. The poles are colder because they don't get direct sunlight. The sun is always low on the horizon.
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Which best describes the motion of air particles when a transverse wave passes through them?
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C.
The particles move perpendicular to the direction of the wave.
3 0
3 years ago
What force does a trampoline have to apply to a gymnast to accelerate her straight up at ? Note that the answer is independent o
Andrew [12]

Answer: Force applied by trampoline = 778.5 N

<em>Note: The question is incomplete.</em>

<em>The complete question is : What force does a trampoline have to apply to a 45.0 kg gymnast to accelerate her straight up at 7.50 m/s^2? note that the answer is independent of the velocity of the gymnast. She can be moving either up or down or be stationary. </em>

Explanation:

The total required the trampoline by the trampoline = net force accelerating the gymnast upwards + force of gravity on her.

= (m * a) + (m * g)

= m ( a + g)

= 45 kg ( 7.50 *  9.80) m/s²

Force applied by trampoline = 778.5 N

5 0
3 years ago
If a sample emits 2000 counts per second when the detector is 1 meter from the sample, how many counts per second would be obser
Alona [7]

Answer:

<h2><em>6000 counts per second</em></h2>

Explanation:

If a sample emits 2000 counts per second when the detector is 1 meter from the sample, then;

2000 counts per second = 1 meter ... 1

In order to know the number of counts per second that would be observed when the detector is 3 meters from the sample, we will have;

x count per second = 3 meter ... 2

Solving the two expressions simultaneously for x we will have;

2000 counts per second = 1 meter

x counts per second = 3 meter

Cross multiply to get x

2000 * 3 = 1* x

6000 = x

<em></em>

<em>This shows that 6000 counts per second would be observed when the detector is 3 meters from the sample</em>

5 0
3 years ago
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