A problem solving method that involves trying all possible solutions until one works is using_____.
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The force exerted on his torso by his legs during the deceleration is 4365 N.
<u>Explanation:</u>
Mass of the torso m=45kg
Height of the building s=3.5 m
Decelerating distance=0.71 m
when he jumps to the ground, the only acceleration is acceleration due to gravity g
<u>motion1 from top to ground </u>
initial velocity u=0
we have to calculate final velocity v using the following equation of motion.
use height of the building as the distance s as the jump from top to the ground is only described here.
<u>Motion 2 on the ground</u>
v=0
u=8.3(final velocity of motion 1)
The deceleration after striking the ground can be calculated from the equation of motion
The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.
The equation of force is