Answer:
R (120) = 940Ω
Explanation:
The variation in resistance with temperature is linear in metals
ΔR (T) = R₀ α ΔT
where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC
let's calculate
ΔR = 1000 (-0,0005) (120-0)
ΔR = -60
Ω
ΔR = R (120) + R (0) = -60
R (120) = -60 + R (0)
R (120) = -60 + 1000
R (120) = 940Ω
I believe the answer should be the last option. upon interaction, both objects should have the same charge after the electrons are transferred.
Explanation:
London dispersion forces will form between non-polar molecules(polar ) that are symmetrical like O₂, H₂, Cl₂ and noble gases.
- The attraction here is because non-polar molecules becomes polar due to the constant motion of its electrons.
- This lead to an uneven charge distribution at an instant.
- A temporary dipole or instantaneous dipole forms.
- The temporary dipole can induce neighboring molecules to be distorted and forms dipoles as well.
- This forms london dispersion forces.
Learn more:
Intermolecular forces brainly.com/question/10602513
#learnwithBrainly
Answer:
v=77.62 m/s
Explanation:
Given that
h= - 300 m
speed of the bird ,u= 5 m/s
Lets take Speed of the berry when it hit the ground = v m/s
we know that ,if object is moving upward
v² = u² - 2 g h
u=Initial speed
v=Final speed
h=Height
Now by putting the values
v² = u² - 2 g h
v² = 5² - 2 x 10 x (-300) ( take g = 10 m/s²)
v² =25 + 20 x 300
v² ==25 + 6000
v² =6025
v=77.62 m/s
Therefore the final speed of the berry will be 77.62 m/s.
Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = 
V = Potential applied = 2 mV
k = Dielectric constant = 40
= Electric constant = 
Capacitance is given by

Charge is given by

Number of electron is given by

The number of charge carriers that will accumulate on this capacitor is approximately 289282.