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3 years ago

Power output of an engine is with work (w=60,000) during 60 s Calculate the power of this work?*

Physics

1 answer:

igomit [66]3 years ago

6 0

Answer:

<em>The power output of the engine is 1,000 Watt</em>

Explanation:

<u>Mechanical Power </u>

Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.

The power can be calculated as:

$\displaystyle P=\frac {W}{t}$

Where W is the work and t is the time.

The engine does a work of W=60,000 J during t=60 s. Calculate the power:

$\displaystyle P=\frac {60,000}{60}$

P = 1,000 Watt

The power output of the engine is 1,000 Watt

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3 years ago

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2 years ago

If we increase the force applied to an object, and all other factors remain the same, the amount of work will

soldier1979 [14.2K]

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3 years ago

Read 2 more answers

Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq

Ulleksa [173]

The charge on each the balloon is 100nC or 1.2 × 10^-7 C

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The charge on each balloon can be found from

$F_{e} = \frac{k_{e}q^{2} }{r^{2}} \\q = \sqrt{\frac{k_{e}q^{2} }{r^{2}}} \\\\q = \sqrt{\frac{(2\times10^{-3N}(0.25m)^{2}}{8.99\times10^{9}N\cdotm^{2}/C^{2}}\\$

$q = 1.2\times10^{-7}C$ or 100nC

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. The matter is positively charged if it contains more protons than electrons and negatively charged if it contains more electrons than protons.

Learn more about the charge here:

brainly.com/question/14713274

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1 year ago

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

Elan Coil [88]

Answer:

$a=0.284\ m/s^2$

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2$

So, the acceleration experienced by the occupants of the spaceship is $0.284\ m/s^2$ .

5 0

3 years ago