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levacccp [35]
3 years ago
13

An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f

ield on the surface of the wire is measured to be B1. The experiment is then repeated with the same current but with a wire of diameter 2d. The magnetic field measured on the surface of this second wire will be which of the following?
B1, B1 / 4, 4B1, B1 / 2
Physics
1 answer:
Anton [14]3 years ago
5 0

Answer:

B_2 = \frac{B_1}{2}

Explanation:

As per Ampere's law the magnetic field at the surface of the wire is given as

\int B. dL = \mu_0 i

here we have

B . (\pi d) = \mu_0 i

so we will have

B_1 = \frac{\mu_0 i}{\pi d}

now again we use same value of current but wire with double the diameter

so the magnetic field at the surface is given as

B_2 = \frac{\mu_0 i}{2\pi d}

so we have

B_2 = \frac{B_1}{2}

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Heat always transfers from substances with _____ thermal energy to substances with _______ thermal until both substances reach t
Reika [66]

Heat always transfers from substances with high thermal energy to substances with low thermal until both substances reach the maximum temperature

4 0
2 years ago
A distance of 0.002 m separates two objects of equal mass. If the gravitational force between them is
Alika [10]

Answer: 24.97 kg

Explanation:

The gravitational force between two objects of masses M1, and M2 respectively, and separated by a distance R, is:

F = G*(M1*M2)/R^2

Where G is the gravitational constant:

G = 6.67*10^-11 m^3/(kg*s^2)

In this case, we know that

R = 0.002m

F = 0.0104 N

and that M1 = M2 = M

And we want to find the value of M, then we can replace those values in the equation to get

0.0104 N = (6.67*10^-11 m^3/(kg*s^2))*(M*M)/(0.002m)^2

(0.0104 N)*(0.002m)^2/(6.67*10^-11 m^3/(kg*s^2)) = M^2

623.69 kg^2 = M^2

√(623.69 kg^2) = M = 24.97 kg

This means that the mass of each object is 24.97 kg

6 0
3 years ago
An MRI scanner is based on a solenoid magnet that produces a large magnetic field. The magnetic field doesn't stop at the soleno
GaryK [48]

Answer:

The maximum change in  flux is \Delta \o = 0.1404 \ Wb

The average  induced emf     \epsilon =0.11232 V

Explanation:

   From the question we are told that

             The speed of the technician is v = 0.80 m/s

              The distance from the scanner is d = 1.0m

              The  initial magnetic field is  B_i = 0T

               The final magnetic field is B_f = 6.0T

                 The diameter of the loop is  D = 19cm = \frac{19}{100} = 0.19 m

The area of the loop is mathematically represented as

        A  =  \pi [\frac{D}{2} ]^2

             = 3.142 \frac{0.19}{2}

             = 0.02834 m^2

At maximum the change in magnetic field is mathematically represented as

            \Delta \o = (B_f - B_i)A

  =>      \Delta  \o = (6 -0)(0.02834)

                  \Delta \o = 0.1404 \ Wb

The  average induced emf is mathematically represented as

           \epsilon =  \Delta \o v

              = 0.1404 * 0.80

             \epsilon =0.11232 V

7 0
3 years ago
What are the benefits of solar cookers?
Elanso [62]

Answer:

Using clean, renewable, and readily available solar energy as fuel.

Preserving natural resources by not requiring the use of wood or other biomass fuels to cook.

Not producing dangerous emissions which pollute local environments and contribute to climate change.

Explanation:

5 0
3 years ago
Read 2 more answers
Please, I need help with this.
solmaris [256]

this is the answer :)

6 0
3 years ago
Read 2 more answers
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