All categories

3 years ago

Name the regions of a electromagnetic spectrum from the shortest wavelength to the longest wavelength

Physics

1 answer:

kaheart [24]3 years ago

5 0

Answer:

From shortest wavelength to longest wavelength:

Gamma Rays

X-Rays

Ultraviolet

Visible Light

Infrared waves

Microwaves

Radio Waves

Explanation:

You might be interested in

Identify the constants and variables in 2cm +4y

Harman [31]

constant = 2 and 4

variable = y

Explanation:

A constant is usually a symbol with a known value. In the expression, the constants are 2 and 4.

Their values are accurately known.

A variable is place holder and the value is not known. Variables are not static. They can take different numerical values as defined by an equation:

2cm +4y

the cm is the a unit

2 and 4 are constants

y is a variable that can assume any value

Learn more:

Experiment brainly.com/question/1621519

#learnwithBrainly

4 0

3 years ago

Is quartzite a mineral, a rock, or neither?

Licemer1 [7]

It’s a metamorphic rock, so for that it’s rock I also enjoy that anime

3 0

2 years ago

Date: 12-3-21<br> 4.<br> The momentum of a 5-kilogram object moving at<br> 6 meters per second is

ASHA 777 [7]

Answer

30 kg . m/sec

Explanation:

mark me as brainliest!

5 0

2 years ago

Read 2 more answers

A 0.150 kg stone rests on a frictionless, horizontal surface. A bullet of mass 9.50 g, traveling horizontally at 380 m/s, strike

Anvisha [2.4K]

Answer:

(a)Magnitude=28.81 m/s

Direction=33.3 degree below the horizontal

(b) No, it is not perfectly elastic collision

Explanation:

We are given that

Mass of stone, M=0.150 kg

Mass of bullet, m=9.50 g= $9.50\times 10^{3} kg$

Initial speed of bullet, u=380 m/s

Initial speed of stone, U=0

Final speed of bullet, v=250m/s

a. We have to find the magnitude and direction of the velocity of the stone after it is struck.

Using conservation of momentum

$mu+ MU=mv+ MV$

Substitute the values

$9.5\times 10^{-3}\times 380 i+0.150(0)=9.5\times 10^{-3} (250)j+0.150V$

$3.61i=2.375j+0.150V$

$3.61 i-2.375j=0.150V$

$V=\frac{1}{0.150}(3.61 i-2.375j)$

$V=24.07i-15.83j$

Magnitude of velocity of stone

= $\sqrt{(24.07)^2+(-15.83)^2}$

|V|=28.81 m/s

Hence, the magnitude and direction of the velocity of the stone after it is struck, |V|=28.81 m/s

Direction

$\theta=tan^{-1}(\frac{y}{x})$

= $tan^{-1}(\frac{-15.83}{24.07})$

$\theta=tan^{-1}(-0.657)$

=33.3 degree below the horizontal

(b)

Initial kinetic energy

$K_i=\frac{1}{2}mu^2+0=\frac{1}{2}(9.5\times 10^{-3})(380)^2$

$K_i=685.9 J$

Final kinetic energy

$K_f=\frac{1}{2}mv^2+\frac{1}{2}MV^2$

= $\frac{1}{2}(9.5\times 10^{-3})(250)^2+\frac{1}{2}(0.150)(28.81)^2$

$K_f=359.12 J$

Initial kinetic energy is not equal to final kinetic energy. Hence, the collision is not perfectly elastic collision.

5 0

3 years ago

If you throw a ball down ward then acceleration immeditely after leaving your hand is

bezimeni [28]

Answer:

9.8m/s²

Explanation:

The acceleration of the ball thrown after leaving my hand is 9.8m/s². This will be the acceleration due to gravity on the body.

Acceleration due to gravity is caused by the pull of the earth on a massive object.
The value of this acceleration is 9.8m/s².
As the ball nears the surface, it comes near zero.

7 0

3 years ago