Answer:
c is the right answer for the problem
Answer:
Step-by-step explanation:
Let x represent the amount invested at 11%. Then (5400-x) is the amount invested at 8%. The total interest earned is the sum of the interest amounts earned on each investment. Each of those is the product of the interest rate and the amount invested.
(5400-x)·8% + x·11% = 522
432 +0.03x = 522 . . . . . . . . simplify
.03x = 90 . . . . . . . . . . . . . . . subtract 432
90/.03 = x = 3000 . . . . . . . . divide by the coefficient of x
$3000 is invested at 11%; $2400 is invested at 8%.
Answer:
hb ≈ 7.06cm
Step-by-step explanation:
Using the formulas:
A=hbb
2
A=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving for <em>hb</em>
hb=﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4
2b=﹣154+2·(15·17)2+2·(15·8)2﹣174+2·(17·8)2﹣84
2·17
≈7.05882cm
I guess =ay=6-3x= ay/y=6-3x/y= a=6-3x/y
Answer:
19 6/10, 19, -8/40, -19.4
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