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Airida [17]
3 years ago
8

Heeeeeelp 5). A sector of a circle with the centre angle 120° is

Mathematics
1 answer:
Stella [2.4K]3 years ago
5 0

Answer:

i forgo

Step-by-step explanation:

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Elijah ran around the quarter mile track at the school seven times. Approximately how many kilometers is this?
Ivan
I would say the answer is C
3 0
3 years ago
A randomized trial tested the effectiveness of diets on adults. Among 36 subjects using Diet 1, the mean weight loss after a yea
seropon [69]

Answer:

The 95%  confidence interval is

           0.45 <  \mu_1 - \mu_2  < 5.35

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1   =  36

   The first  sample mean is  \= x_1  =  3.5

   The first standard deviation is  \sigma_1  =  5.9 \ pounds

   The second  sample size is n_2 =  36

    The second  sample mean is  \= x_2 =  0.6

    The second  standard deviation is \sigma  =  4.4

Generally the degree of freedom is mathematically represented as

     df =  \frac{ [ \frac{s_1^2 }{n_1 }  + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2  }

=>  df =  \frac{ [ \frac{5.9^2 }{34 }  + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2  }

=>  df =63

Generally the standard error is mathematically represented as

      SE =  \sqrt{ \frac{s_1 ^2 }{n_1}  + \frac{s_2^2 }{ n_2 } }

=>  SE =  \sqrt{ \frac{ 5.9 ^2 }{ 36 }  + \frac{ 4.4^2 }{36} }

=>  SE = 1.227

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

     t_{\frac{\alpha }{2}, 63  } =  1.998

Generally the margin of error is mathematically represented as

        E =  t_{\frac{\alpha }{2}, 63  } *  SE

=>    E =  1.998 * 1.227

=>    E =  2.45

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 - \x_2) -E <  \mu

 => (3.5  - 0.6) - 2.45 <  \mu_1 - \mu_2  < (  3.5  - 0.6)  + 2.45

=>   0.45 <  \mu_1 - \mu_2  < 5.35

     

8 0
2 years ago
What sample size is needed to give a margin of error within plus-or-minus 5% in estimating a population proportion with 90% conf
VARVARA [1.3K]

Answer: 271.

Step-by-step explanation:

When the prior population proportion of success is not available, then the formula to find the sample size is given by :-

n=00.25(\dfrac{z_{\alpha/2}}{E})^2

Given : Significance level : \alpha: 1-0.90=0.1

By using the standard normal distribution table ,

Critical value : z_{\alpha/2}=1.645

Margin of error : E=0.05

Then , the required minimum sample size will be :-

n=0.25(\dfrac{(1.645)}{0.05})^2=270.6025\approx271

Hence, the required minimum sample size is 271.

4 0
3 years ago
Aaron sold half of his comic books and then bought sixteen more. He now has 36. With how many did she begin?
Leni [432]

Answer:

40

Step-by-step explanation:

36-16 = 20

20*2=40

Lets check - half comic books - 40/2= 20 + 16 more = 36

4 0
3 years ago
Help Please ASAP thanks
Fittoniya [83]
Your answer would definitely be the 3rd answer choice.
6 0
3 years ago
Read 2 more answers
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