3 years ago

Heeeeeelp 5). A sector of a circle with the centre angle 120° is

Mathematics

1 answer:

Stella [2.4K]3 years ago

5 0

Answer:

i forgo

Step-by-step explanation:

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Marta_Voda [28]

From the Pythagorean Theorem:

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4 years ago

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Ghella [55]

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First off, you <em>never</em> want square roots on the bottom of a fraction, so let's multiply both sides by $\sqrt{2x}$ to get rid of it. All we have to do from there is simplify!

$\frac{\sqrt{8x^2}}{\sqrt{2x}}*\frac{\sqrt{2x}}{\sqrt{2x}}=\frac{\sqrt{8x^2}*\sqrt{2x}}{2x}}=\frac{\sqrt{16x^3}}{2x}=\frac{4x\sqrt{x}}{2x}=\boxed{2\sqrt{x}}$

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irakobra [83]

Answer:

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Step-by-step explanation:

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