<span>The substance that is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(I), and molten magnesium iodide, mgi2(I), can be expressed as Ca2+ + 2eâ’ --> Ca. At the anode, the substance can be expressed as 2Brâ’ â’ 2eâ’ --> Br2. At the cathode for magnesium iodide can be expressed as Mg2+ + 2 eâ’ --> Mg, and 2 Iâ’ â’ 2 eâ’ --> I2 at the anode.</span>
It can only do that when one of the components of the mixture is a magnetic
material.
When you have that situation, you pass the magnet over the mixture ... shaking
the mixture if it's a dry mixture of powders or pieces ... and the magnetic part of
the mixture moves toward the magnet, while the nonmagnetic parts of the mixture
couldn't care less about the magnet and they just stay where they are.
Answer:
Ok then
Explanation:
Thank you for the free points! Have a good day.
Answer: C; it will also change from a gas to a liquid at 78°C while the gas loses energy.
Explanation:
Took the test. If it boils at 78°C, then that means it will be either a liquid turning into a gas, or a gas turning into a liquid. If the gas loses energy, that means it is being cooled, so if a gas loses energy at 78°C, it will become a liquid.
Let us assume that there is a 100g sample present. The respective mass of each element will then be:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Now, we divide each constituent's mass by its Mr to obtain the moles of each
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Dividing by the smallest number:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula is
C10H12NO
