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Shtirlitz [24]
3 years ago
13

Please help!!! Explain the type of graph that could be used for the data below.

Physics
1 answer:
sdas [7]3 years ago
7 0
Answer:

A table or chart
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Solid are _______, usually in a regular repeating pattern
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particles or arranged will be the answer depending on the previous line.

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Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle
LenKa [72]

Answer : The de-Broglie wavelength of this electron, 0.101\AA

Explanation :

The formula used for kinetic energy is,

K.E=\frac{1}{2}mv^2        ..........(1)

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{mv}

or,

v=\frac{h}{m\lambda}      ...........(2)

Now put the equation (2) in equation (1), we get:

\lambda=\frac{h}{\sqrt{2\times m\times K.E}}  ...........(3)

where,

\lambda = wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.11\times 10^{-31}Kg

K.E = kinetic energy = 4.71\times 10^{-15}J

Now put all the given values in the above formula (3), we get:

\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}

\lambda=1.0115\times 10^{-11}m=0.101\AA

conversion used : (1\AA=10^{-10}m)

Therefore, the de-Broglie wavelength of this electron, 0.101\AA

7 0
3 years ago
The membrane of the axon of a nerve cell is a thin cylindrical shell of radius r = 10-5 m, length L = 0.32 m, and thickness d =
maksim [4K]

Answer:

5.3 x 10⁻⁹ C

Explanation:

r = radius of cylindrical shell = 10⁻⁵ m

L = length = 0.32 m

A = area

Area is given as

A = 2πrL

A = 2 (3.14) (10⁻⁵) (0.32)

A = 20.096 x 10⁻⁶ m²

d = separation = 10⁻⁸ m

k_{appa} = dielectric constant = 4

Capacitance is given as

Q=\frac{k_{appa}\epsilon _{o}A}{d}                               eq-1

V = Potential difference across the membrane = 74 mV = 0.074 Volts

Q = magnitude of charge on each side

Magnitude of charge on each side is given as

Q = CV

using eq-1

Q=\frac{k_{appa} \epsilon _{o}AV}{d}

Inserting the values

Q=\frac{4 (8.85\times 10^{-12})(20.096\times 10^{-6})(0.074)}{10^{-8}}

Q = 5.3 x 10⁻⁹ C

4 0
3 years ago
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