A simple pendulum makes 120 complete oscillations in 3.00 min at a location where g 5 9.80 m/s2. Find (a) the period of the pend
1 answer:
Answer:
(a) 1.5 second
(b) 0.56 m
Explanation:
Pendulum makes 120 oscillations in 3 min that means in 180 seconds
time taken by the pendulum to complete one oscillation is called time period.
(a) So, the time period is 180 / 120 = 1.5 second
T = 1.5 second
Thus, the time period of the pendulum is 1.5 second.
(b) g = 9.8 m/s^2
The formula for the time period is given by
Where, L be the length of pendulum
L = 0.56 m
Thus, the length of the pendulum is 0.56 m .
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Answer:
The correct answer is
Explanation:
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where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.
Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is . Converting this number to m³ using very elementary unit conversion we get
. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,
if we convert the area from mm³ to m³ we get .So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,
which is our final answer.
Answer:
The car traveled the distance before stopping is 90 m.
Explanation:
Given that,
Mass of automobile = 2000 kg
speed = 30 m/s
Braking force = 10000 N
For, The acceleration is
Using newton's formula
Where, f = force
m= mass
a = acceleration
Put the value of F and m into the formula
Negative sing shows the braking force.
It shows the direction of force is opposite of the motion.
For the distance,
Using third equation of motion
Where, v= final velocity
u = initial velocity
a = acceleration
s = stopping distance of car
Put the value in the equation
Hence, The car traveled the distance before stopping is 90 m.