Which of the following account for the difference between radio waves , infrared waves, and ultraviolet rays?

Physics

2 answers:

gayaneshka [121]3 years ago

5 0

Answer: B

The only difference between these different types of radiation is their wavelength or frequency

Explanation:

vaieri [72.5K]3 years ago

4 0

Answer:

The answer is B. frequency and D. wavelength for APX.

Explanation:

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A constant force of 12 N acts for 5 s on a 5 kg object. What is the change in object’s velocity?

sattari [20]

Answer:

"solve: given that F -12 N and time 4 seconds and let we have to find out the P.

F = 12 N

t = 4 s

p = ?

F = m×( v - u ) / t

12 = m×v / 4

m×v = 12× 4

p = 48 kg m/s

Linear momentum will be 48 kg m/s.

Explanation:

7 0

3 years ago

An object of mass 0.9 kg is attached to a massless string of length 3 m, and swung with 3 a tangential velocity of 3 m/s. What i

Ganezh [65]

Answer:

Explanation:

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3 years ago

A certain airport runway of length L allows planes to

PilotLPTM [1.2K]

The length of the new runway In terms of (L) is 4L.

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<em>Your question is incomplete, it seems your question is missing the following information below;</em>

"In terms of (L) , what must be the length of the new runway?"

The given parameters;

length of the runway, = L

let the take off speed = V₁

For the newly designed planes;

the take off speed is double of the original = 2V₁

the acceleration for both take is constant = a

The take off speed for the given constant acceleration is given as;

$v^2 = u^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\a = \frac{v^2}{2s} \\\\$

The length of the new runway In terms of (L) is calculated as follows;

$a = \frac{v_1^2}{2s_1} = \frac{v_2^2}{2s_2} \\\\substitute \ the \ corresponding \ values \ for \ initial \ acceleration \ and \ new \\acceleration\\\\\frac{v_1^2}{2L} = \frac{(2v_1)^2}{2s_2}\\\\2s_2v_1^2 = 2L(4v_1^2)\\\\s_2 = \frac{2L(4v_1^2)}{2v_1^2} = \frac{8Lv_1^2}{2v_1^2} = 4L$