Why does the originally neutral hair and balloon become charged

1 answer:

3 0

Answer: Because When two objects, such as your hair and the balloon rub together, one loses some of its electrons to the other. This makes one object positively charged and the other object negatively charged. This movement of the electrons causes the neutral object to get a low positive charge.

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Can I please have help

NeTakaya

Answer:

it will usually increase

Explanation:

potato

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2 years ago

Convert 592 minutes to seconds. using one step conversion.

vovangra [49]

Answer:

35520

Explanation:

592 times 60=35520

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2 years ago

Comic-book superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is tak

Katena32 [7]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

shear stress is the measure of the material's resistance to cause "sliding" motion of its layers.
<span>Since the hero has to take a cylindrical piece of metal out, the area which will cause this force is 2*pi*r*l (put r and l in SI units to get answer in Newtons) </span>
<span>so the force required is shear strength into this area (2.60109 * 2 * pi * r * l) </span>

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3 years ago

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.0

ivolga24 [154]

Since you solved a and b I will start with part c.
Part C
To answer this question we need to find zeros of a velocity function:
$v(t)=0.04t^3-0.06t^2$
We can factor this polynomial:
$v(t)=0.04t^3-0.06t^2=t^2(0.04t-0.06)$
Now it's pretty easy to find zeros. This function will be equal to zero when any of the factors are equal zero.
$t^2=0;\\ 0.04t-0.06=0$
We solve these two equations and we get our zeros:
$t_1=0; t_2=\frac{3}{2}$
The particle is at rest at t=0 and t=3/2.
Part D
To solve this we need to determine when our velocity function is greater than zero. We will use factored form.
We determine when each factor is greater than zero and with that information, we build the following table:
$\centering \label{my-label} \begin{tabular}{lllll} Range & -\infty & 0 & 3/2 & +\infty \\ t^2 & - & + & + & + \\ 0.04t-0.06 & - & - & + & + \\ t^2 (0.04t-0.06) & + & - & + & + \end{tabular}$
We can see, from the table, that our function is positive when $- \infty < t$ and t>3/2.
That is the range in which particle is moving in positive direction.
Part E
We know that distance traveled is given with:
$s(t)=0.01t^4 - 0.02t^3$
We simply plug in t=12 to find total distance traveled:
$s(12)=0.01(12)^4 - 0.02(12)^3=172.80 ft$
Part F
We know that acceleration is defined as a rate of change of velocity.
We find acceleration by taking the first derivative of velocity with respect to time.
$a(t)=\frac{dv}{dt}=(0.04t^3-0.06t^2)'=0.12t^2-0.12t$
To find acceleration after 1 second we simply plug in t=1s in above equation:
$a(1)=0.12-0.12=0$

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3 years ago

If one wall of a room consists of a large flat mirror, how much larger will the

kiruha [24]

Answer:

The room will appear to be twice as big because the object distance is equal to the image distance. The mirror takes into account the distance between the mirror and how big the room is.

8 0

2 years ago