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alexdok [17]
3 years ago
5

NEED HELP ASAP 20 Points Might need a calculator

Mathematics
2 answers:
Talja [164]3 years ago
7 0
The slope of the line in the picture is 1x or just x.
Sergio039 [100]3 years ago
4 0
1/1 or just 1 the slope is rise over run
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Find the distance between each pair of point. Round to the nearest hundredth(-8, -2) and (6, -1)
Murljashka [212]

Answer:

the square root of 197

Step-by-step explanation:

delta x=14

delta y=1

therefore with the Pythagorean theorem, the hypotenuse/distance is the square root of 197

7 0
3 years ago
Which graph matches the exponential function f(x) = (3)x?
kondaur [170]
What are the graphs?
4 0
3 years ago
Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81
Anton [14]
Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)

with partial derivatives (set equal to 0)

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}
L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}
L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}
L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81

Substituting the first three equations into the fourth allows us to solve for \lambda:

x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}

For each possible value of \lambda, we get two corresponding critical points at (\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3).

At these points, respectively, we get a maximum value of f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3 and a minimum value of f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3.
5 0
3 years ago
It is recommended that one fire extinguisher be available for every 6000 feet in the building write and solve an equation to det
Ulleksa [173]
135,000 divided by 6000 =22.5
x = 22.5
7 0
3 years ago
Read 2 more answers
What is the solution set for z+10=z-2
photoshop1234 [79]

Answer: No Solution.

There are no values of z that make the equation true.

Step-by-step explanation:


5 0
3 years ago
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