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3 years ago

What changes occurred when you heated sugar ? Please help Test

1 answer:

8 0

When sugar is first heated, it begins to melt. As it melts its color starts to change from white to golden brown, and then to dark brown (if you continue heating it). If you apply heat for even longer, it becomes black and gives off unpleasant fumes.

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12 pts needing help with this physics question

miskamm [114]

Answer:

the second one i believe. (the water exerts an external force on the fish in the opposite direction, pushing the fish forward.)

Explanation:

4 0

3 years ago

Which of the following statements about transition metals is true?

Levart [38]

It would probably be C

7 0

3 years ago

Read 2 more answers

a particle is moving with shm of period 8.0s and amplitude 5.0cm. find (a) the speed of particle when it is 3.0m from the centre

Fudgin [204]

Answer:

a) $speed=\pi cm/s$

b) $v_{max}=\frac{5\pi}{4} cm/s$

c) $a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}$

Explanation:

The very first thing we must do in order to solve this problem is to find an equation for the simple harmonic motion of the given particle. Simple harmonic motion can be modeled with the following formula:

$y=Asin(\omega t)$

where:

A=amplitude

$\omega$ = angular frequency

t=time

we know the amplitude is:

A=5.0cm

and the angular frequency can be found by using the following formula:

$\omega=\frac{2\pi}{T}$

so our angular frequency is:

$\omega=\frac{2\pi}{8s}$

$\omega=\frac{\pi}{4}$

so now we can build our equation:

$y=5sin(\frac{\pi}{4} t)$

we need to find the speed of the particle when it is 3m from the centre of its motion, so we need to find the time t when this will happen. We can use the equation we just found to get this value:

$y=5sin(\frac{\pi}{4} t)$

$3=5sin(\frac{\pi}{4} t)$

so we solve for t:

$sin(\frac{\pi}{4} t)=\frac{3}{5}$

$\frac{\pi}{4} t=sin^{-1}(\frac{3}{5})$

$t=\frac{4}{\pi}sin^{-1}(\frac{3}{5})$

you can directly use this expression as the time or its decimal representation:

t=0.81933

since we need to find the speed of the particle at that time, we will need to get the derivative of the equation that represents the particle's position, so we get:

$y=5sin(\frac{\pi}{4} t)$

$y'=5cos(\frac{\pi}{4} t)*\frac{\pi}{4}$

which simplifies to:

$y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)$

and we can now substitute the t-value we found previously, so we get:

$y'=\frac{5\pi}{4}cos(\frac{\pi}{4} (0.81933))$

$y'=\pi$

so its velocity at that point is $\pi$ cm/s

b) In order to find the maximum velocity we just need to take a look at the velocity equation we just found:

$y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)$

its amplitude will always give us the maximum velocity of the particle, so in this case the amplitude is:

$A=\frac{5\pi}{4}$

so:

$v_{max}=\frac{5\pi}{4} cm/s$

c) we can use a similar procedure to find the maximum acceleration of the particle, we just need to find the derivative of the velocity equation and determine its amplitude. So we get:

$y'= \frac{5\pi}{4}cos(\frac{\pi}{4} t)$

We can use the chain rule again to find this derivative so we get:

$y" =-\frac{5\pi}{4}sin(\frac{\pi}{4} t)*(\frac{pi}{4})$

so when simplified we get:

$y"=-\frac{5\pi^{2}}{16}sin(\frac{\pi}{4} t)$

its amplitude is:

$A=\frac{5\pi^{2}}{16}$

so its maximum acceleration is:

$a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}$

7 0

3 years ago

Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv

shusha [124]

Answer:

Two.

Explanation:

A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.

One complete wave consists of two loops.
It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.

8 0

3 years ago

How do you graph motion in physics? How do you graph motion in physics? I've seen problems state that an object is in free fall

Dahasolnce [82]

This is Kinematics and the equations in your book.

A speed time graph would plot the speed of something against the teime it was at a speed.

If it were changing it speed constantly, that would be a straight line if acclerating. Total distrance would be the area under the graph.

5 0

3 years ago