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3 years ago

Convert 500,000 inches into miles

Physics

2 answers:

Alex Ar [27]3 years ago

5 0

Answer:

7.89141414 miles.

Explanation: hope this helps. :)

olga nikolaevna [1]3 years ago

3 0

Answer: 7.89141414

Explanation:

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PLEASE ANYONE CAN HELP ME !E.x/A block of metal has a volume of 0.09 m3

LuckyWell [14K]

Answer:

B = 1058.4 N

Explanation:

Given that,

The volume of a metal block, V = 0.09 m³

The density of fluid, d = 1200 kg/m³

We need to find the buoyant force when it's Completely immersed in brine. The formula for the buoyant force is given by :

$B=\rho gV$

g is acceleration due to gravity

$B=1200\times 9.8\times 0.09\\\\B=1058.4\ N$

So, the required buoyant force is 1058.4 N.

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3 years ago

Which of the following correctly describes the first animals that appeared?

Anettt [7]

A these were large creatures similar to dinosaurs

5 0

4 years ago

An automobile can be considered to be mounted on four identical springs as far as vertical oscillations are concerned. The sprin

tresset_1 [31]

Answer:

a) 120341 N/m

b) 1.432 Hz

Explanation:

Given that

Frequency of oscillations of spring, F = 3.27 Hz

Mass of the car, m = 1140 kg

Average mass of passengers, M = 68 kg

The mass on each spring,

m = 1/4 m,

m = 1140 / 4

m = 285 kg

The spring constant on each spring, k is

ω = √(k/m), also,

ω = 2πf, so that

2πf = √(k/m)

If we square both sides, then

4π²f² = k/m

k = 4π²f²m if we substitute, we have

k = 4 * 3.142² * 3.27² * 285

k = 120341 Nm

Since the mass of each person is 68 kg, then the total mass of all passengers would be

68 * 5 = 340 kg

Thus, the total mass of the oscillating system is,

mass of passengers + mass of car

340 kg + 1140 kg

M(total) = 1480 kg

To get the vibrating frequency, we substitute for values in the equation

2πf = √(k/m)

F = 1/2π * √(k/m)

F = 1/2π * √(120341 / 1480)

F = 1/2π * √81.31

F = 0.1591 * 9

F = 1.432 Hz

7 0

4 years ago

Building codes usually limit the current carried by a No. 14 copper wire to 15 A. Many household circuits are wired with this si

Sedbober [7]

Answer:

The drift velocity of the electrons in this case is c) 5.52 x 10-4 m/s

Explanation:

First of all, we need to find the volume occupied by 63.3g of copper, so $V=\frac{m}{\rho}= \frac{0.0633Kg}{8,900kg/m^{3}} =7.11 \times 10^{-6} m^{3}$ , then if we assume each atom of copper contributes with one free electron to the material body $n=\frac{N_{A}}{V}=\frac{6.02 \times 10^{23} electrons}{7.11 \times 10^{-6} m^{3}} =8.46 \times 10^{28} electrons/m^{3}$ .

Finally, we apply $v_{d}=\frac{I}{nqA}$ , where A is area so, $A=\pi (\frac{d}{2})^{2}= \pi (\frac{0.0016m}{2})^{2}=2 \times 10^{-6} m^{2}$ , thus $v_{d}=\frac{I}{nqA}=\frac{15C/s}{(8.46 \times 10^{28} m^{-3})(1.60 \times 10^{-19} C)(2 \times 10^{-6} m^{2})}=5.50 \times 10^{-4} m/s$ .

As we can see c. 5.52 x 10-4 m/s is the nearest one.

3 0

3 years ago

If the toy car moved with a velocity of 2m/s to the south for 8s; what is the total displacement of the toy car?

ElenaW [278]

Try calculating maybe that would help you

3 0

3 years ago