you and 3 friends apply a combined force of 489.5n to push a piano. The amount of work done is 1762.2j. What distance did the pi
1 answer:
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Complete Question
The diagram of this question is shown on the first uploaded image
Answer:
The distance the block slides before stopping is
Explanation:
The free body diagram for the diagram in the question is shown
From the diagram the angle is
Where
So
From the question we are told that
The mass of the block is
The mass of the pendulum is
The velocity of the pendulum at the bottom of swing is
The coefficient of restitution is
The coefficient of kinetic friction is
The velocity of the block after the impact is mathematically represented as
Where is the velocity of the block before collision which is 0
Substituting value
According to conservation of energy principle
The energy at point a = energy at point b
So
Where
is the potential energy at A which is mathematically represented as
= 0 at the bottom
is the kinetic energy at A which is mathematically represented as
is the potential energy at B which is mathematically represented as
From the diagram
is the kinetic energy at B which is 0 (at the top )
Where is is the workdone against velocity which from the diagram is
So
Substituting values
So
Answer:
The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²
The rocket's motion for analysis sake is divided into two phases.
Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m
Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.
Explanation:
The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.
The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.
The detailed step by step solution to the problems can be found in the attachment below.
Thank you and I hope this solution is helpful to you. Good luck.
