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4 years ago

How do electrons in a metallic bond behave?

Chemistry

1 answer:

igomit [66]4 years ago

4 0

Hello,

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

Hope this helps!!!! Happy Holidays!!!! (:

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TRUE - FALSE

inessss [21]

Answer:

True

Explanation:

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3 years ago

How many protons does an atom of Iodine (I), #53, have if it has an atomic mass of 127?

Vilka [71]

Iodine has 53 protons. The atomic number is always the same as the number of protons that element has.

3 0

3 years ago

Find the molarity of 131 g Ba(NO3)2 dissolved in 750.0 water

storchak [24]

Answer:

6.68 x 10^-4

Explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

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8 0

2 years ago

When 18.9 kJ is transferred to a gas sample in a constant volume adiabatic container with a calorimeter constant of 2.22 Kj/K, t

poizon [28]

Answer:

(a) Cgas = 0.125 kJ/k

(b) cgas = 0.25kJ/kg.K

Explanation:

18.9 kJ is equal to the sum of the heat absorbed by the gas and the heat absorbed by the calorimeter.

Qcal + Qgas = 18.9 kJ [1]

We can calculate the heat absorbed using the following expression.

Q = C . ΔT

where,

C is the heat capacity

ΔT is the change in the temperature

(a) What is the heat capacity of the sample?

From [1],

Ccal . ΔT + Cgas . ΔT = 18.9 kJ

(2.22kJ/K) × 8.06 K + Cgas × 8.06 K = 18.9 kJ

Cgas = 0.125 kJ/k

(b) If the sample has a mass of 0.5 kilograms, what is the specific heat capacity of the substance?

We can calculate the specific heat capacity (c) using the following expression:

$c=\frac{C}{m} =\frac{0.125kJ/K}{0.5kg} =0.25kJ/kg.K$

(c) If the sample is Krypton, what is the molar heat capacity at constant volume of Krypton? The molar mass of Krypton is 83.8 grams/mole.

The molar heat capacity is:

$\frac{0.25kJ}{kg.K} .\frac{1kg}{1000g} .\frac{83.8g}{mol} =0.021kJ/mol.K$

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3 years ago

In covalent bonds atmosphere share electrons so that?

professor190 [17]

The electons are in the atmosphere

6 0

3 years ago