Answer: N3 H12 P O3
Explanation:
From the question :
N = 31.57% H = 9.10% P = 23.27%
O= 36.06%
Divide each of the element by their respective relative atomic masses.
N = 31.57 / 14 = 2.26
H = 9.10/ 1 = 9.10
P = 23.27 / 31= 0.750
O =36.06 / 16 = 2.25
Divide each answer by the lowest of them all, we then have:
N = 2.26/ 0.750 = Approx = 3
H = 9.10 / 0.750 = Approx = 12
P = 0.750/ 0.750= 1
O = 2.25 / 0.750 = Approx = 3
The empiral formula is
N3 H12 P O3
Answer:
130.4 grams of sucrose, would be needed to dissolve in 500 g of water.
Explanation:
Colligative property of boiling point elevation:
ΔT = Kb . m . i
In this case, i = 1 (sucrose is non electrolytic)
ΔT = Kb . m
0.39°C = 0.512°C/m . m
0.39°C /0.512 m/°C = m
0.762 m (molality means that this moles, are in 1kg of solvent)
If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles
Molar mass sucrose = 342.30 g/m
Molar mass . moles = mass
342.30 g/m . 0.381 m = 130.4 g
7. Neutralisation. Which would (obviously) appear GREEN on the chart.
Answer:
v2=40.35L
Explanation:
p1v1/t1=p2v2/t2
v2=t2p1v1/t1p2
v2=984*760*22.4/273.15*1520
v2=40.35 L
We have to look for safe and non - hazardous characterstics when trying to find new propellants.
<h3>What are propellants ?</h3>
Propellants are any gas, liquid, or solid the expansion of which can be used to impart motion to another substance or object.
The Desirable properties for propellant combinations are ;
- low molecular mass and high temperature of reaction products (for high exhaust velocity),
- high density (to minimize tank weight),
- low hazard factor (e.g., corrosivity and toxicity),
- low environmental impact,
- low cost.
Learn more about propellants here ;
brainly.com/question/1395855
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