Answer:
Plants are found in the domain of eukarya
I think the answer is true if so i hope it helps
The result for TEST FOR LIFE is that the sample produces ATP. The sample is plant.
D Is going to be your answer
Explanation:
The chloroplasts are cell structures that are photosynthesis. The Golgi apparatus is the site transport of substance out of the cell. Mitochondria is the site of cellular respiration.
The two main functions of organelle is that it stores the herediatary material, DNA and it coordinates the cell's activities like growth, intermediary metabolism, protein synthesis, and reproduction. Eukaryotes are the cells of advanced organisms have a nucleus.
The results of the sample produces ATP, the sample is plant and the plant cells have an envelope surrounding the nucleus.
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<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>
What is benzoic acid found in?
- Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
- Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.
Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.
Amount of moles of NaOH -2 × 0.025 = 0.05 mol
Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol
In this case, we can calculate the pH produced by the buffer of these two reagents, as follows
We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows
Now we must solve the equation above. This will be done using the following values
With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.
NaOH volume
( 0.5 - 0.464)L
0.036L .................... 36ml
HCOOH volume
500 - 36 = 464mL
Learn more about benzoic acid
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Answer : The initial temperature of system 2 is,
Explanation :
In this problem we assumed that the total energy of the combined systems remains constant.
The mass remains same.
where,
= heat capacity of system 1 = 19.9 J/mole.K
= heat capacity of system 2 = 28.2 J/mole.K
= final temperature of system =
= initial temperature of system 1 =
= initial temperature of system 2 = ?
Now put all the given values in the above formula, we get
Therefore, the initial temperature of system 2 is,