Answer:
Identify the indicated protons in the following molecules as unrelated, homotopic, enantiotopic, or diastereotopic. a) Methyls a & b: _________ b) Ha & Hc: ________
Explanation:
Homotopic hydrogens:
Consider two hydrogens in the given molecule and replace one by one with a different atom say for example deuterium, then if the two molecules formed by replacing hydrogens are the same then the two hydrogens are called homotopic hydrogens.
After replacing the two hydrogens with a different atom then, enantiomers are formed then, the two hydrogens are called enantiotopic hydrogens.
After replacing the two hydrogens with a different atom then, diastereomers are formed then, the two hydrogens are called diastereotopic hydrogens.
In the methyl group, select two hydrogens and replace one hydrogen atom with a D-atom name the compound.
Again replace another hydrogen atom with D-atom.
Name it.
If both are the same then, the hydrogens are homotopic and they are shown below:
Hence, they are homotopic protons.
Answer:
Homo nuclear molecule mean having atoms of only one element,
I cant see clearly the option B and C can you correct them , 2002? Hz?
Explanation:
Answer:
–4020 KJ
Explanation:
The following data were obtained from the question:
H₂(g) + F₂(g) —> 2HF(g) ΔH = –536 KJ
Next, we shall determine the mass of H₂ that reacted from the balanced equation to produce –536 KJ of heat energy. This can be obtained as follow:
Molar mass of H₂ = 2 × 1 = 2 g/mol
Mass of H₂ from the balanced equation = 1 × 2 = 2 g.
Summary:
From the balanced equation above,
2 g of H₂ reacted to produce –536 KJ of heat energy.
Finally, we shall determine the heat change produced by the reaction of 15 g of H₂. This can be obtained as follow:
From the balanced equation above,
2 g of H₂ reacted to produce –536 KJ of heat energy.
Therefore, 15 g of H₂ will react to produce = (15 × –536)/2 = –4020 KJ of heat energy.
Thus, the heat change for the reaction is –4020 KJ