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kicyunya [14]
2 years ago
7

Kijoknmgg hv jnb vcxvbnbvcvbnmnbvmnb

Chemistry
1 answer:
Vaselesa [24]2 years ago
4 0
Kijoknm
gg hv jnb vcxbnbvcvbnmnbvmnb
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What shape does N2H4 have? (linear, bent, planar, pyramid, tetrahedral, or none)
Salsk061 [2.6K]
The N2H4 bond angle will be probably 109 degrees. Since, well,<span> it has a bent </span>trigonal pyramidal<span> geometry.</span>
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3 years ago
Số oxi hóa của các nguyên tố: Fe(OH)2; Fe(OH)3; FexOy; Zn(OH)2 là gì
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esfsef

Explanation:

esfsefseF

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There are two types of nucleic acids, dna and rna. nearly all organisms use dna, not rna, as the central repository for genetic
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3 years ago
How does radioactive isotopes decay?
aksik [14]
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7 0
3 years ago
Calculate the standard free-energy change at 25 ∘C for the following reaction:
lianna [129]

Answer:

Standard free-energy change at 25^{0}\textrm{C} is -3.80\times 10^{2}kJ/mol

Explanation:

Oxidation: Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)

Reduction: Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)

--------------------------------------------------------------------------------------

Overall: Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)

Standard cell potential, E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}

So, E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V

We know, standard free energy change at 25^{0}\textrm{C}(\Delta G^{0}): \Delta G^{0}=-nFE_{cell}^{0}

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, \Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol

8 0
3 years ago
Read 2 more answers
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