What is the surface area of the square-based pyramid?
1 answer:
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For this case we have the following equation:
Where,
I: <span>the intensity of a given sound
I0: </span><span> the threshold of a hearing intensity
</span>Substituting values in the given equation we have:
<span />
<span />Rewriting the equation we have:
<span />
<span />Then, by properties of logarithm we have:
<span />
<span />Finally we have:
<span />
<span />Answer:
T<span />he intensity, in decibles, [I(dB)], when I=10^8(I0) is:
D.80
Where,
I: <span>the intensity of a given sound
I0: </span><span> the threshold of a hearing intensity
</span>Substituting values in the given equation we have:
<span />
<span />Rewriting the equation we have:
<span />
<span />Then, by properties of logarithm we have:
<span />
<span />Finally we have:
<span />
<span />Answer:
T<span />he intensity, in decibles, [I(dB)], when I=10^8(I0) is:
D.80
Answer:
The area of the triangle is 351cm^2.
Step-by-step explanation:
To find the area of a triangle, the formula is (1/2) x base x height. In this case, the height would be a line that cuts straight through the center of the triangle. However, this height is not given to us. We can still find it through Pythagoras' Theorem though.
Let A be the tip of the triangle, and B and C be the points on either side of the triangle. Assuming an imaginary line that cuts the triangle in a symmetrical half, let T be the point at the end of the line, directly below point A.
Using Pythagoras' Theorem,
AB^2 = AT^2 + TB^2
AT^2 = AB^2 - TB^2
AT^2 = 30^2 - (26/2)^2
AT^2 = 30^2 - 13^2
AT =
AT = 27.0370116692
So the length of AT is our height. We can now find the area of the triangle.
Area of triangle = (1/2) x 26cm x AT
Area of triangle = 351.4811516996
Area of triangle = 351cm^2 (To 3s.f.)