Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
Lesser x = -9
Greater x = 9
Step-by-step explanation:
To answer this question you need to first set up the small, medium, large number of cakes as a ratio with a total. From here you will create a new ratio of the correct number of small medium and large Cakes sold using the total 216. The factor would be to multiply by nine. -Step 1 in picture. After this you would read what the relationship is between a medium and a small and the large and the small profits are - Step 2 in picture. After this you would represents the total profit based on the number of small medium and large cakes that were sold. Making this equal to L648.45. To find the profit for one small, you would then divide 648.45 by the 495 you got when you simplify the expression. The answer is L1.31.
Answer:
A right triangle is always 90 degrees.
Step-by-step explanation:
Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:

By the Central Limit Theorem




Z = 2:




The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213