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mylen [45]
2 years ago
13

Dr. Keller has a bookcase in her office with three shelves each shelf has the same number of books on it there are 23 books on t

he top shelf what is the total number of books on Dr. Keller’s bookcase
Mathematics
1 answer:
KiRa [710]2 years ago
7 0

Answer:

69

Step-by-step explanation:

23 on each shelf x 3 shelves = 69 books

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Type the correct answer in each box. Use numerals instead of words. Any non-integer answers in this problem should be entered as
ladessa [460]

Answer:

The interquartile range of the data set is 5

The mean absolute deviation of the data set is 3.6

Step-by-step explanation:

* Lets explain how to find the interquartile range and the mean absolute

  deviation (MAD)

- The steps to find the interquartile range is:

1- Arrange the values from the smallest to the largest

∴ The values are 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

2- Find the median

- The median is the middle value after arrange them

* If there are two values in the middle take their average

∵ The values are 10 then the 5th and the 6th are the values

∵ The 5th is 12 and the 6th is 13

∴ The median = \frac{12+13}{2}=12.5

∴ The median is 12.5

3- Calculate the median of the lower quartile

- The lower quartile is the median of the first half data values

∵ There are 10 values

∴ The first half is the first five values

∴ The first half values are 5 , 6 , 10 , 11 , 12

∵ The middle value is 10

∴ The median of lower quartile = 10

- Similar find the median of the upper quartile

- The upper quartile is the median of the second half data values

∵ There are 10 numbers

∴ The second half is the last five values

∴ The second half values are 13 , 14 , 15 , 18 , 20

∵ The middle value is 15

∴ The median of upper quartile = 15

4- The interquartile range (IQR) is the difference between the upper

    and the lower medians

∴ The interquartile range = 15 - 10 = 5

* The interquartile range of the data set is 5

* Lets talk about the mean absolute deviation

- Mean absolute deviation (MAD) of a data set is the average distance  

 between each data value and the mean

- To find the mean absolute deviation of the data, start by finding

   the mean of the data set.  

1- Find the sum of the data values, and divide the sum by the  

   number of data values.  

∵ The data set is 5 , 6 , 10 , 11 , 12 , 13 , 14 , 15 , 18 , 20

∵ Its sum = 5 + 6 + 10 + 11 + 12 + 13 + 14 + 15 + 18 + 20 = 124

∵ The mean = the sum of the data values/the number of the data

∵ The set has 10 numbers

∴ The mean = 124/10 = 12.4

2- Find the absolute value of the difference between each data value  

   and the mean ⇒ |data value – mean|

# I5 - 12.4I = 7.4

# I6 - 12.4I = 6.4

# I10 - 12.4I = 2.4

# I11 - 12.4I = 1.4

# I12 - 12.4I = 0.4

# I13 - 12.4I = 0.6

# I14 - 12.4I = 1.6

# I15 - 12.4I = 2.6

# I18 - 12.4I = 5.6

# I20 - 12.4I = 7.6

3- Find the sum of the absolute values of the differences.

∵ Their sum = 7.4 + 6.4 + 2.4 + 1.4 + 0.4 + 0.6 + 1.6 + 2.6 + 5.6 + 7.6

∴ Their sum = 36

4- Divide the sum of the absolute values of the differences by the

    number of data values  to find MAD

∴ MAD = The sum of the absolute values/number of the values

∵ The sum = 36

∵ The data set has 10 values

∴ MAD = 36/10 = 3.6

* The mean absolute deviation of the data set is 3.6

6 0
2 years ago
Which algebraic expression represents the phrase “fourteen increased by a number”?
agasfer [191]

Answer:

the answer is B

Step-by-step explanation:

James James James jams James sano a ao

3 0
3 years ago
Read 2 more answers
6. (CED.2, REI. 6) A manager is comparing
Mariulka [41]
I think the answer for this question is the second one
6 0
2 years ago
This is a linear equations question so pls help me I’m dying of stress thank you! ^^
topjm [15]

Answer:

the answer to this problem is D:(-2,4)(1,1)

7 0
2 years ago
Read 2 more answers
A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate
sdas [7]

Answer:

442 miles

Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

x^2 + 1^2 = y^2

Differentiate w.r.t time (t)

2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}

2x\frac{dx}{dt} = 2y\frac{dy}{dt}

Divide both sides by 2

x\frac{dx}{dt} = y\frac{dy}{dt}

From the question, we have that the plan travels are 510mi/h.

This implies that:

\frac{dx}{dt} = 510mi/h

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

y = 2mi

Apply Pythagoras theorem

x^2 + 1^2 = y^2

x^2 + 1^2 = 2^2

x^2 + 1 = 4

x^2 = 4-1

x^2 = 3

x = \sqrt 3

So, the expression becomes:

x\frac{dx}{dt} = y\frac{dy}{dt}

\sqrt 3 * 510 = 2* \frac{dy}{dt}

\frac{\sqrt 3 * 510}{2} =  \frac{dy}{dt}

\sqrt 3 * 255 =  \frac{dy}{dt}

\frac{dy}{dt} = 255\sqrt 3

\frac{dy}{dt} = 255 * 1.7321

\frac{dy}{dt} = 441.655

\frac{dy}{dt} = 442

<em>Hence, the distance is 442 miles</em>

7 0
3 years ago
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