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3 years ago

Which physical phenomenon causes the spherical shapes of raindrops

Physics

1 answer:

jeyben [28]3 years ago

6 0

Answer:

Raindrops start to form in a roughly spherical structure due to the surface tension of water. This surface tension is the "skin" of a body of water that makes the molecules stick together. The cause is the weak hydrogen bonds that occur between water molecules.

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A 10,844.0 kg truck is initially at rest. The truck then accelerates across a level road and reaches a constant speed. It takes

lara [203]

Answer:

1,634.1 W

Explanation:

Power = work / time

P = 41,505.4 J / 25.4 s

P = 1,634.1 W

7 0

3 years ago

A police car on the side of the road (at rest) uses a radar gun to catch speeders as they approach it. The frequency the radar g

oee [108]

Answer:

$\Delta f = 1.49 \times 10^9 Hz$

Explanation:

Apparent frequency that is received to the speeder is given as

$f_1 = f_0\frac{v + v_o}{v}$

$f_1 = (8 \times 10^9)\frac{340 + v_o}{340}$

here we know that

$v_o = 65 mph = 29 m/s$

now we have

$f_1 = (8 \times 10^9)\frac{340 + 29}{340}$

$f_1 = 8.68 \times 10^9 Hz$

now the frequency that is received back from the speeder is given as

$f_2 = f_1\frac{v}{v- v_o}$

$f_2 = (8.68 \times 10^9}\frac{340}{340 - 29}$

$f_2 = 9.49 \times 10^9 Hz$

So difference is the frequency is given as

$\Delta f = 9.49 \times 10^9 - 8 \times 10^9$

$\Delta f = 1.49 \times 10^9 Hz$

4 0

3 years ago

Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, $\mu _k$ = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = $\mu _k$ ×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

$\mu _k$ = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = $\mu _k$ ×m×g×s

1/2·v² = $\mu _k$ ×g×s

v² = 2× $\mu _k$ ×g×s = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

3 0

3 years ago

A boat covered 5/9 of a journey at an average speed of 25

Lera25 [3.4K]

Answer:

Thus, the time for the remaining 120 miles: 8.5 - 6 = 2.5 h

Explanation:

The remaining 120 miles was (1 - 5/9 = 4/9) of the total journey.

Then, total distance: 120 ÷ 4/9 = 120 × 9/4 = 270 miles

The distance for 25 mph: 270 × 5/9 = 150 miles

The time for 25 mph: 150 ÷ 25 = 6 h

7 0

3 years ago

Alice is driving down the road at 86 m/s when she sees a speed limit sign for 7m/s. What is

ollegr [7]

Answer:

$-9.875 m/s^{2}$

Explanation:

Acceleration, $a=\frac {v-u}{t}$

Where v and u are the final and initial velocities of Alice's car respectively, t is the time taken for Alice's car to attain velocity of 7 m/s.

Substituting 7 m/s for v, 86 m/s for u and 8 s for t then

$a=\frac {7-86}{8}=-9.875 m/s^{2}$

Therefore, the car decelerates at a rate of $9.875 m/s^{2}$

6 0

4 years ago