Answer: proton, hydrogen nucleus, hydrogen atom
Newton taught us: Force = (mass) x (acceleration)
Divide each side by (mass) : Acceleration = (force) / (mass) .
The only problem here is: This formula applies when the "Force" is the
only force on the object. When the objects in these school problems are
falling out of airplanes, shot from guns, or being hit by baseball bats, we
routinely ignore the force of air resistance against the object. We're
comfortable with that, maybe because it's become a habit. But now,
we're not so comfortable about ignoring the force of water resistance.
All I can tell you is that if you DO ignore the water resistance, that is,
if the water were not there, her acceleration would be
(250 newtons) / (70 kg) = 3.57 m/s² = about 0.36 g .
But what is it really, in the water ?
If you've spent any substantial amount of time anywhere near competitive
swimmers, then you know that it depends on their position coming off the
wall, what they do with their knees and knuckles, how straight they hold
their body, how deep the texture of their swim-cap is, and how well they've
shaved their legs.
Answer:
The maximum torque on the loop is 395.80 N.m.
Explanation:
Given;
number of turns of the wire, N = 150 turns
length of the square loop, L = 18.0 cm = 0.18 m
current in the wire, I = 50.9 A
Magnetic field, B = 1.6 T
Maximum torque on the loop is given by;
τ = NIAB
τ = (150)(50.9)(0.18²)(1.6)
τ = 395.80 N.m
Therefore, the maximum torque on the loop is 395.80 N.m.
The average velocity = Displacement between two points/ Time taken for that displacement
In this case An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k
So, displacement = 4.0 i + 8.0 j - 6.0 k - (8.0 i - 4.0 j + 3.0 k)
= -4.0 i + 12.0 j - 9.0 k
So velocity, V = (-4.0 i + 12.0 j - 9.0 k)/8
= -0.5 i + 1.5 j - 1.125 k
So average velocity during 8 seconds = -0.5 i + 1.5 j - 1.125 k
The answer is C since the higher up you go the colder it gets which is why Linda will experience colder climates.
