All categories

2 years ago

A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.

2 answers:

7 0

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

The body is gaining the speed, which means there is a change in kinetic energy.
The change in kinetic energy is equal to the work done.
The friction force is the product of coefficient of the friction and normal force.
The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

Zarrin [17]2 years ago

4 0

Answer:

Explanation:

The normal force will be perpendicular to the motion. A zero-work situation is one where "a force everywhere perpendicular to the motion does no work" so according to this principle, no work is done.

You might be interested in

5)List an appropriate SI base unit (with a prefix as needed ) for the following:

AlexFokin [52]

B) kg
d) cm
e)kg
g) km
h) kg

5 0

3 years ago

Read 2 more answers

1. Two wires - A and B - with circular cross-sections have identical lengths and are made of the same material. Yet, wire A has

PolarNik [594]

Answer:

Diameter of wire B is 2 times the diameter of wire A

Explanation:

We have given two wire A and B

They are made up of same material and length of both the wire is sane

So $l_A=l_B$

Let the resistivity of both the wire is $\rho$

It is given that wire A has 4 times the resistance as wire B

So $R_A=4R_B$

So $\frac{\rho l_A}{a_A}=4\frac{\rho l_B}{a_B}$ ( As $l_A=l_B$ )

$\frac{a_A}{a_B}=\frac{1}{4}$

$\frac{d_A^2}{d_B^2}=\frac{1}{4}$

$\frac{d_A}{d_B}=\frac{1}{2}$

$d_B=2d_A$

So diameter of wire B is 2 times the diameter of wire A

6 0

3 years ago

A particle moving along the y-axis has the potential energy u =4y3j, where y is in m. what is the y-component of the force on th

Ivenika [448]

Potential energy is given as

$U = 4y^3$

now as we know that force is related by potential energy by the formula

$F = - \frac{dU}{dy}$

So it is gradient of energy with position in Y

$F = - \fracd(4y^3}{dy}$

$F = -12y^2 \hat j$

Now at y = 0

$F = 0 N$

at y = 1

$F = - 12*1^2$

$F = - 12 N$

at y = 2

$F = - 12*2^2$

$F = - 48 N$

so above is the forces at given positions

7 0

3 years ago

Nio conducts a science experiment. He puts yeast into a bottle with water and sugar, and then caps the bottle with a balloon. He

KATRIN_1 [288]

Answer: Option (C) is the correct answer.

Explanation:

When yeast is added into a bottle with water and sugar then after some time yeast becomes activated. This results in the formation of a chemical change as bubbles are formed on the surface of the mixture in the bottle.

This indicates that a gas has been released due to the chemical change.

Thus, we can conclude that most likely a chemical change has occurred because a gas was produced.

3 0

3 years ago

Read 2 more answers

A research team developed a robot named Ellie. Ellie ran 1,000 meters for 200 seconds from the research building, rested for 100

Verizon [17]

Answer:

1. Running velocity (5 m/s)

2. Resting velocity (0 m/s)

3. Walking velocity (-1 m/s)

1. Running speed (5 m/s)

2. Walking speed (1 m/s)

3. Resting speed (0 m/s)

Explanation:

Attached you will find the plot of position vs time of Ellie´s movement.

The velocity is the displacement of the object over time relative to the system of reference. The speed, in change, is the traveled distance over time in disregard of the system of reference.

So, the velocity is calculated as follows:

v = Δx / Δt

where

Δx = final position - initial position

Δt = elapsed time

1) The average velocity of Ellie while running is:

v = 1000 m - 0 m / 200 s = 5 m/s

While resting:

v = 0 m - 0 m / 100 s = 0 m/s

And while walking back:

v = 0 m - 1000 m / 1000 s = - 1 m/s

Note that in this last case, the initial position is 1000 m because Ellie is 1000 m from the origin of the system of reference when she walks back. The final position will be the origin of the system of reference, 0 m.

Comparing with the graphic, the velocity is the slope of the function position(t).

Then:

1. Running velocity (5 m/s)

2. Resting velocity (0 m/s)

3. Walking velocity (-1 m/s)

2) The speed is the distance traveled over time:

Running speed = 1000 m / 200 s = 5m /s

Resting speed = 0 m / 100 s = 0 m/s

Walking speed = 1000 m/ 1000 s = 1 m/s

Then:

1. Running speed (5 m/s)

2. Walking speed (1 m/s)

3. Resting speed (0 m/s)

4 0

3 years ago