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MariettaO [177]
3 years ago
10

Let f(x) = 6x2 + 5 and g(x) =3x -5. Find g(f(2))

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0

Answer:

g(f(2)) = 82

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 6x² + 5

g(x) = 3x - 5

<u>Step 2: Find g(f(2))</u>

f(2)

  1. Substitute:                    f(2) = 6(2)² + 5
  2. Exponents:                   f(2) = 6(4) + 5
  3. Multiply:                        f(2) = 24 + 5
  4. Add:                              f(2) = 29

g(f(2))

  1. Substitute:                    g(29) = 3(29) - 5
  2. Multiply:                        g(29) = 87 - 5
  3. Subtract:                       g(29) = 82
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Answer: 14.9^{\circ}

Step-by-step explanation:

Given

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the area of a rectangle is 30 to the square root of 3750 square inches, and the length is 3 to the square root of 250 inches. wh
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<h3><u>Answer</u><u>:</u></h3>

  • \sf { width =10 \sqrt{15} \:inches}

<h3><u>Solution</u><u>:</u></h3>

<em>We are given that:</em>

  • Area of rectangle is 30√3570
  • Length of the rectangle is 3√250

<u>Area </u><u>of </u><u>rectangle </u><u>is </u><u>given </u><u>by:</u>

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<u>Hence, putting the values in the formula:</u>

\implies\quad \sf{ A = l\times w}

\implies\quad \sf{ 30\sqrt{3750}=3\sqrt{250}\times w}

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\implies\quad \sf{ w =\dfrac{30\sqrt{3750}}{3\sqrt{250}}}

\implies\quad \sf{ w =10\dfrac{\sqrt{3750}}{\sqrt{250}}}

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