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nevsk [136]
3 years ago
7

When your heart doesn't know what it wants.. what do you do?

Chemistry
1 answer:
DENIUS [597]3 years ago
3 0
Follow your nose to the fruity taste of chows recharge the heart then follow your heart good luck my friend

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How do we get the essential amino acids we need
kherson [118]

Answer: through your diet

3 0
3 years ago
What is a property that describes how easily a substance undergoes chemical changes?
dedylja [7]
Reactants are the substances that undergo changes and the new substance created from it is called products.
5 0
3 years ago
Choose the aqueous solution below with the highest freezing point. These are all solutions of nonvolatile solutes and you should
GrogVix [38]

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

Kf = freezing point constant

m = molality

i = Van't Hoff factor

The  Van't Hoff factor has to do with the number of particles in solution. Let us consider the  Van't Hoff factor for each specie.

0.200 m HOCH2CH2OH - 1

0.200 m Ba(NO3)2 - 3

0.200 m K3PO3 - 4

0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

8 0
2 years ago
Fundamental differences in the cell, the basic unit of life, allow for broadest classification of all living organisms into thre
Nana76 [90]

Answer:

C

Explanation:

7 0
2 years ago
A liquid of density 1290 kg/m 3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the
Gelneren [198K]

Answer:

114 kPa

Explanation:

By Bernoulli's equation when a fluid flows steadily through a pipe:

P + ρ*g*y + v² = constant in the pipe, where P is the pressure, ρ is the density of the fluid, g is the gravity acceleration (9.8 m/s²), y is the high, and v the velocity.

By the continuity equation, the liquid flow must be constant in the pipe, and then:

A1*v1 = A2*v2

Where A is the area, v is the velocity, 1 is the point 1, and 2 the point 2 in the pipe. The are is the circle area: π*(d/2)². So:

π*(0.105/2)²*9.91 = π*(0.167/2)²*v2

0.007v2 = 0.027

v2 = 3.9 m/s

Then:

P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²

ρ*g*y1 - ρ*g*y2 + v1² - v2² = P2 - P1

ρ*g*Δy + v1² - v2² = ΔP

ΔP = 1290*9.8*9.01 + 9.91² - 3.9²

ΔP = 113,987.42 Pa

ΔP = 114 kPa

8 0
2 years ago
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