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AleksAgata [21]
3 years ago
5

People who are reading this:

Computers and Technology
2 answers:
Mandarinka [93]3 years ago
7 0
Thank u boo but kinda creepy ☺️
Gnom [1K]3 years ago
3 0

Answer:

Awe thanks hun!

Explanation:

You might be interested in
These data provides the responses of 10 students in class A and in class B who were asked how many hours they slept lastThese da
dmitriy555 [2]

Answer:

Answer C

Explanation:

Class A Median: 4, 5, 6, 6, 7, 7, 7, 7, 8, 8

The Median of Class A is 7.

Class B Median: 5, 6, 6, 6, 7, 7, 7, 8, 8, 9

The Median of Class B is 7.

Class A Mean: 4 + 5 + 6 + 6 + 7 + 7 + 7 + 7 + 8 + 8 = 65

To find the mean, you add all of the numbers together, and divide the total by the amount of numbers. (There are ten numbers in the equation, so we divide 65 by 10.)

65/10 = 6.5, This means that the mean of Class A is 6.5

Class B Mean: 5 + 6 + 6 + 6 + 7 + 7 + 7 + 8 + 8 + 9 = 69

Do the same thing as last time, divide 69 by 10. (6.9)

The mean of class B is 6.9

Answer A and B are both incorrect, because the medians for both classes were the same.  Answer C is correct, because the mean of class B was 6.9 and the mean of Class A was 6.5

Answer D is also incorrect, 6.9 is 0.4 greater than 6.5

Solved by Inspire! (14 years old)

3 0
3 years ago
The term ____ means that a public information network such as an Internet service provider (ISP) should treat all users, all pla
Softa [21]

Answer:

Domain Name System

Explanation:

The Domain Name System is a hierarchical and decentralized naming system for computers, services, or other resources connected to the Internet or a private network. It associates various information with domain names assigned to each of the participating entities

5 0
3 years ago
Light travels at 3 × 108 meters per second. A light-year is the distance a light beam travels in one year.Write a PYTHON program
Volgvan

Answer: This is a python code

def lightyear():

   rate=3*100000000   //speed of light

   seconds=365*24*60*60   //number of seconds in 1 year

   return str((rate*seconds)/1000)+" km"    //distance=speed x time

print(lightyear()) //will print value of light hear in kilometers

OUTPUT :

9460800000000.0 km

Explanation:

In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.

4 0
3 years ago
Visual Basics: 1 ) Write an if/else statement that compares the double variable pH with 7.0 and makes the following assignments
Lemur [1.5K]

Answer:

visual basic: 1)

Module PHmodule

   Sub Main()

       'Creating a variable for each entity

       dim ph as double = 0.0, neutral,base,acid as boolean

       'Writing a line to show user what to do

       console.writeline("Enter the pH :")

       'Taking the value

       ph=console.readline()

       'using if & elseif statement for distingushing the values into correct catagories

       if ph<7.0 then

       neutral=false:base=false:acid=true

       elseif ph>7.0 then  

       neutral=false:base=true:acid=false

       elseif ph=7.0 then

       neutral=true:base=false:acid=false

       end if

       'Printing the result

       console.writeline(" Neutral :" & Neutral)

       console.writeline(" base :" & base)

       console.writeline(" acid :" & acid)

       'command for staying in the command prompt for reading the result

       console.readline()

   End Sub

End Module

visual basic: 2)

Module AGEmodule()

  Sub Main()

       'Creating a variable for each entity

       dim age,minors,adults,seniors as integer = 0

       'Taking age from user

       console.writeline("Enter the age")

       age=console.readline()

       'using if & elseif statement for checking the age differnce

       if age<18 then'

       minors +=1

       else if age>18 and age<64 then

       adults +=1

       else if age>64 then  

       seniors +=1

       end if

       'printing result

       console.writeline("minors="&minors)

       console.writeline("adults="&adults)

       console.writeline("seniors="&seniors)

       'command for reading the result  

       console.readline()

  End Sub

End Module

Explanation:

visual basic 1) it is very simple program which allow us to find if the substance is acidic, basic or neutral. we use sim statement for making a variable as double (gives value in decimal) which allow to take a value from the user through console.readline() command and then by using the if statement we apply the condition if the ph is less then, greator then or equal to 7.0 value. thus the program gives us the answer. console.writeline() command is used to print a command on the screen while console.readline() command let us read the lines until we press enter.

visual basic 2)a program which allow us to count and add number of persons according to their age. we use dim statement for creating the variable as integers in which we take the age from user and then after checking it through if statement we increment according to three categories i.e. minors, adults, seniors. the console.writeline() command allow us to print anything on screen and console.readline() allowus to take value while compiling.

thank you...

6 0
3 years ago
QUESTION
Lady_Fox [76]

Answer:

Explanation:

#include <iostream>

using namespace std;

int main ()

{

   int responses[30],count[6];

   int score = 0;

   string resp = " ";

   for (int i = 0; i < 30; i++)

   {

    responses[i] = 0;

   }

   for (int i = 0; i < 6; i++)

   {

    count[i,1]=0;

    count[i,2]=0;

    count[i,0]=0;

   }

   while ((resp != "Y") && (resp != "y"))

   {

    for (int i = 0; i < 30; i++)

    {

        while ((score > 5) || (score < 1))

           {

            cout << "Student " << (i+1)<< " please enter a value (1-5):";

            cin >> score;

        }

           responses[i] = score;

           if((score > 5)||(score<1))

           {

               if(score==1) count[1]++;        

               if(score==2) count[2]++;        

               if(score==3) count[3]++;        

               if(score==4) count[4]++;        

               if(score==5) count[5]++;        

           }

           score = 0;

    }

    cout<< "Response               Frequency              Percentage"<<endl;;

    cout<< "    1                      "<<count[1]<<"               "<<(count[1]/30)<<"%"<<endl;

    cout<< "    2                      "<<count[2]<<"               "<<(count[2]/30)<<"%"<<endl;

    cout<< "    3                      "<<count[3]<<"               "<<(count[3]/30)<<"%"<<endl;

    cout<< "    4                      "<<count[4]<<"               "<<(count[4]/30)<<"%"<<endl;

    cout<< "    5                      "<<count[5]<<"               "<<(count[5]/30)<<"%"<<endl;

    cout<< "Do you want to exit? Press Y to exit any other key to continue: ";

    cin>> resp;

   }

   return 0;

}

8 0
3 years ago
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