What is 8/36 minus 3/14? Subtracting unlike fractions
2 answers:
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So for the rhombus to carry onto itself, it needs to start in one position and end up in that same position. In this case, (x,y) will need to end up on (x,y) after the reflections are done. Here what the options do:
A: y-axis, x-axis, y-axis
(x,y) -> (-x,y) -> (-x,-y) -> (x,-y)
B: x-axis, y-axis, y-axis
(x,y) -> (x,-y) -> (-x,-y) -> (x,-y)
C: y=x, x-axis, y=x, y-axis
(x,y) -> (y,x) -> (y,-x) -> (-x,y) -> (x,y)
D: x-axis, y=x, x-axis, y=x
(x,y) -> (x,-y) -> (-y,x) -> (-y,-x) -> (-x,-y)
The only option that starts as (x,y) and ends as (x,y) is C: y=x, x-axis, y=x, y-axis, therefore making that the correct answer.
Split up the interval [0, 3] into 3 equally spaced subintervals of length . So we have the partition
[0, 1] U [1, 2] U [2, 3]
The left endpoint of the -th subinterval is
where .
Then the area is given by the definite integral and approximated by the left-hand Riemann sum