It's a value you should probably memorize:

You can derive it using some trigonometric identities, other known values of cosine, and properties of the cosine function. For example, using the double angle identity for cosine:

If
, then

and you probably know that
, so

When we take the square root, we should take the positive root because
whenever
:

Answer:
see diagram
Step-by-step explanation:
A rectangle has the area that can be calculated using formula

1. Consider rectangle with length of 8 yards and width of 6 yard. Then

2. Consider rectangle with length of 12 yards and width of 4 yard. Then

These two rectangles are attached.
Answer:
5.42$
Step-by-step explanation:
Please mark brainliest?
Answer:
Option c is correct .
Step-by-step explanation:
May this help you !!!!!!!!