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QveST [7]
3 years ago
9

Pls help these are fractions btw.

Mathematics
1 answer:
vichka [17]3 years ago
6 0
<h3><u>S</u><u>olution</u></h3>

1). 1/3 + 1/5 = (5 + 3)/15

= 8/15. Ans.

2).

==> 3/5 - 1/6

= (3×5 - 5)/30

= (15 - 5)/30

= 10/30

= 1/3 Ans.

3).

==> 2/3 ÷ 3/4

= 2/3 × 4/3

= 8/9 Ans.

4).

==> 3/8 + 5/12

= (3×3 + 10)/24

= (9+10)/24

= 19/24 Ans.

5).

==> 5/16 - 3/32

= (5×2 - 3)/32

= (10-3)/32

= 7/32 Ans.

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Answer:

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To find the circumcenter, solve any two bisector equations and find out the intersection points. The given are A(1,1), B(0,2), and C(3,-2).Midpoint of AB = (1/2, 3/2)  - You can get the midpoint by getting the average of x-coordinates and y-coordinates. Slope of AB = -1Slope of perpendicular bisector = 1Equation of AB with slope 1 and the coordinates (1/2, 3/2) isy - (3/2) = (1)(x - 1/2) y = x+1Do the same for ACMidpoint of AC = (2, -1/2)Slope of AC = -3/2Slope of perpendicular bisector = 2/3Equation of AC with slope 2/3 and the coordinates (2, -1/2) isy - (-1/2) = (2/3)(x - 2) y = -11/6 + 2x/3So the perpendicular bisectors of AB and BC meety = x+1y = -11/6 + 2x/3To solve for x,(-11/6 + 2x/3) = (x+1)x= -17/2Now get y by substituting y = (-17/2) + 1y = -15/2

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