Need the Answer for this, provide an explanation.
1 answer:
You might be interested in
From general equation of a line;
y=mx+c
m=
m=
m=-1
y=-x+c
Finding value of c;
using point (-2,0)
0=-(-2)+c
c=-2
y=-x-2
y=mx+c
m=
m=
m=-1
y=-x+c
Finding value of c;
using point (-2,0)
0=-(-2)+c
c=-2
y=-x-2
Answer:
x = 150°
Step-by-step explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.
