The shells further away from the nucleus are LARGER and can hold MORE electrons
The answer would look something like this. (sorry for the ugliest diagram ever.)
Formula for Barium Nitrate = Ba(NO3)2
Thus based on stoichiometry:
1 mole of Ba(NO3)2 contains 2 moles of NO3-
Therefore, concentration of nitrate ion NO3- would be = 2*0.240 = 0.480 M
Use the relation:
V1M1 = V2M2
V1 = V2M2/M1 = 0.500 L * 0.0800/0.480 = 0.0833 L
Thus, 0.0833 L or 83.3 ml solution of Ba(NO3)2 would be required.
Answer:
C3H3O
Explanation:
Now, what we need to do is to divide the percentage compositions by the relative atomic masses.
The relative atomic mass of carbon 12, the relative atomic mass of hydrogen is 1 while the atomic mass of oxygen is 16.
We now do the divisions as follows:
Carbon = 63.15/12 = 5.2625
Oxygen = 31.55/16 = 1.971875
Hydrogen = 5.30/1 = 5.30
Now,we now divide by the smallest I.e that of oxygen.
Carbon = 5.2625/1.971875 = 2.668
Oxygen = 1.971875/1.971875 = 1
Hydrogen = 5.3/1.971875= 2.688
We can round up the ratio of carbon and hydrogen to 3.
Thus, the empirical formula is C3H3O
Explanation:
the last CH2 should CH3
because the first and last carbons are bonded to three hydrogens
