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Andrei [34K]
3 years ago
13

How do we get energy from the food we eat?

Chemistry
2 answers:
Doss [256]3 years ago
4 0

Answer:

b. breaking the molecular bonds in the food

Nastasia [14]3 years ago
3 0

Answer:

B

Breaking the molecular bonds in the food releases stored chemical energy.

Explanation:

I hope it helps

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If a question cannot be tested and observed, it cannot be answered with science. (2 points) True or False?
boyakko [2]

Answer:

True

Explanation:

If a question cannot be tested and observed, it cannot simply be answered by science.

Science works with observable and testable ideas and not on metaphysics.

  • Science presents a methodical approach into investigating phenomenon and answering likely questions in a logical manner.
  • The body of facts and data gathered through observations and tests are used to ramify the conclusion of a scientific study.
  • Without such, it is impossible to do the work of science.
3 0
3 years ago
Complete the sentences to explain your reasoning.
tangare [24]

Answer:

I need the columns to do the question

Explanation:

3 0
3 years ago
Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)
Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

learn more about standard molar entropy:

brainly.com/question/15908262

#SPJ4

7 0
2 years ago
(b) difference between metalloids and alloys​
blsea [12.9K]

Answer:

<u>Metalloid -</u>

A metalloid is a chemical element with properties intermediate between those of typical metals and nonmetals

<u>Alloy</u> -

An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

5 0
2 years ago
Read 2 more answers
In the lab you measure a clean dry crucible and cover to be 24.36 grams. You obtain a 2cm piece of pure magnesium metal. After s
mart [117]

Answer:

1) 0.3g Mg

2)0.5g MgO

3)0.2g O

4)0.01mol Mg & 0.01mol O

5)0.01mol MgO

6) Empirical formula MgO

Explanation:

The mass og Mg is obtained by substracting 24.36g from 24.66g:

24.66 - 24.36 = 0.3g Mg

The ignition of Mg means that it's reacting with oxygen to form an oxide. The increase in the crucible mass after the Mg ignition is due to the addition of oxygen. However, the addition of few drops of water produces a new compound: a hydroxide. According to the oxidation state og Mg (2+), the only magnesium oxide possible is MgO. It happens because the oxidation state of oxygen in oxides is 2-. Which means that just one oxygen atom is required to electrically neutralize one magnesium atom.

We can use a conversion factor to know how much MgO is made from from 0.3 g of Mg:

0.3g Mg*\frac{16gO}{24.3gMg}= 0.2g O

Thereby the mass of the oxide is 0.2g O + 0.3g Mg = 0.5g MgO

We convert the mass of oxygen and magnesium to the respective amounts in moles by using conversion factors:

0.2g O*\frac{1 mol O}{16g O}= 0.01mol O

0.3g Mg*\frac{1mol Mg}{24.3g Mg}= 0.01mol Mg

The moles of MgO can be obtained from:

0.5g MgO*\frac{1mol MgO}{40.3g MgO}= 0.01mol MgO

To obtain the empirical formula, the amount fo moles of each elements must be divided by the smallest one, in this case, 0.01.

The result for both number of  Mg atoms and O atoms is 1. This can be interpreted to mean that there is a Mg atom for each O atom forming the  formula unit of the compound.

The step when water is added to the compound resulting after heating does not affect the calculations necessary for the magnesium oxide.

4 0
3 years ago
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