$x^{4}+\frac{1}{x^{4}}-3=x^{4}+\frac{1}{x^{4}}-3 +1 - 1\\\\=x^{4}+\frac{1}{x^{4}} - 2 + 1\\\\= (x^{2})^{2} + (\frac{1}{x^{2}})^{2}- 2 *x^{2}*\frac{1}{x^{2}} - 1\\\\$

$= (x^{2} -\frac{1}{x^{2}})^{2} - 1\\\\=(x^{2}-\frac{1}{x^{2}})^{2}- 1^{2}$

(a² - b²) = (a+b)(a - b)

Here a = x² - (1/x²) and b = 1

$= [ (x^{2}-\frac{1}{x^{2}})+ 1 ] [ (x^{2} -\frac{1}{x^{2}} - 1 ]$

7 0

2 years ago

What is the GCF of 44j^5k^4 and 121j^2k^6?

Leviafan [203]

$44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4$

7 0

2 years ago

Read 2 more answers

Calculate and express your answer in Decimal from 1/2×17

prohojiy [21]

Answer:

8.5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I need help on question 2. Any help is appreciated:)

zlopas [31]

All the y values would be 0, since it’s a horizontal line

3 0

3 years ago