Question

A block of density 8.9g/cm³ measures 5cm by 2cm, Given that the force of gravity is 10N/kg. Determine the maximum pressure

Answer 1

Answer:

Maximum pressure = 4450 N/m²

Explanation:

We'll begin by calculating the volume of the block. This can be obtained as follow:

Volume (V) = 5 cm × 3 cm × 2 cm

V = 30 cm³

Next, we shall determine the mass of the block. This can be obtained as follow:

Density = 8.9 g/cm³

Volume = 30 cm³

Mass =?

Density = mass /volume

8.9 = mass / 30

Cross multiply

Mass = 8.9 × 30

Mass = 267 g

Next, we shall covert 267 g to Kg.

1000 g = 1 Kg

Therefore,

267 g = 267 g × 1 Kg / 1000

267 g = 0.267 Kg

Thus, the mass of the block is 0.267 Kg

Next, we shall determine the force.

Force of gravity (g) = 10 N/Kg

Mass (m) = 0.267 Kg

Force (F) =?

F = mg

F = 0.267 × 20

F = 2.67 N

Next, we shall determine the minimum area since we are trying to obtain the maximum pressure. This can be obtained as follow:

Minimum area = 3 cm × 2 cm

Covert each measurement to metre (m) by dividing each measurement by 100

Minimum area = 0.03 m × 0.02 m

Minimum area = 0.0006 m²

Finally, we shall determine the maximum pressure. This can be obtained as follow:

Force (F) = 2.67 N

Minimum area = 0.0006 m²

Maximum pressure =?

Maximum pressure = Force /minimum area

Maximum pressure = 2.67 / 0.0006

Maximum pressure = 4450 N/m²