Answer:
The average power of the engine of the sports car is 56.32 kW
Explanation:
Given;
mass of the sports car, m = 1100 kg
initial velocity of the sports car, u = 0 m/s
final velocity of the sports car, v = 32 m/s
time of motion, t = 10 s
The kinetic energy of the car is given by;
K.E = ¹/₂m(v² - u²)
K.E = ¹/₂mv²
K.E = ¹/₂ x 1100 x 32²
K.E = 563200 J
The average power of the engine of the sports car is given by;
Pavg = Energy / time
Pavg = 563200 / 10
Pavg = 56320 W
Pavg = 56.32 kW
Therefore, the average power of the engine of the sports car is 56.32 kW
Answer:
Temperature increase = 2.1 [C]
Explanation:
We need to identify the initial data of the problem.
v = velocity of the copper sphere = 40 [m/s]
Cp = heat capacity = 387 [J/kg*C]
The most important data given is the fact that when the shock occurs kinetic energy is transformed into thermal energy, therefore it will have to be:
![E_{k}=Q\\ E_{k}= kinetic energy [J]\\Q=thermal energy [J]\\Re-employment values and equalizing equations\\\\\frac{1}{2} *m*v^{2}=m*C_{p}*dT \\The masses are canceled \\\\dT=\frac{v^{2}}{C_{p} *2} \\dT=2.1 [C]](https://tex.z-dn.net/?f=E_%7Bk%7D%3DQ%5C%5C%20E_%7Bk%7D%3D%20kinetic%20energy%20%5BJ%5D%5C%5CQ%3Dthermal%20energy%20%5BJ%5D%5C%5CRe-employment%20values%20and%20equalizing%20equations%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%3Dm%2AC_%7Bp%7D%2AdT%20%20%5C%5CThe%20masses%20are%20canceled%20%5C%5C%5C%5CdT%3D%5Cfrac%7Bv%5E%7B2%7D%7D%7BC_%7Bp%7D%20%2A2%7D%20%5C%5CdT%3D2.1%20%5BC%5D)
Newton's third law states that for every action, there is an equal and opposite reaction. When you let go of the ballon, you are letting the force out but the force also pushes the balloon back.
Things are rubbed against each other
