Two balls collide in a head-on elastic collision and rebound in opposite directions. One ball has velocity 1.2 m/s before the co
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Answer:
Second projectile is 1.4 times faster than first projectile.
Explanation:
By linear momentum conservation
Pi = Pf
m x U + M x 0 = (m + M) x V
Now Since this projectile + pendulum system rises to height 'h', So using energy conservation:
KEi + PEi = KEf + PEf
PEi = 0, at reference point
KEf = 0, Speed of system zero at height 'h'
PEf = (m + M) g h
So,
So from above value of V
Initial velocity of projectile =U
Now Since mass of projectile and pendulum are constant, So Initial velocity of projectile is proportional to the square root of height swung by pendulum.
Which means
U₂ = 1.41 U₁
Therefore we can say that ,Second projectile is 1.4 times faster than first projectile.
First of all, we need to calculate the work done by the forklift to lift the box of 500 kg by 4 meters. The work done is equal to the variation of gravitational potential energy of the box, given by:
where m=500 kg is the mass of the box,
and 
is the variation of height of the box. Substituting these data into the equation, we find the work
And now we can calculate the minimum power required by the forklift, which is equal to the ratio between the work done and the time taken:
where m=500 kg is the mass of the box,
And now we can calculate the minimum power required by the forklift, which is equal to the ratio between the work done and the time taken: