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igomit [66]
3 years ago
14

Four employees can wash 20 service vehicles in 5 hours. How long would it take 5 employees to wash the same number of vehicles?

Mathematics
2 answers:
kirill [66]3 years ago
3 0

Answer:

Step-by-step explanation:

4 workers × 5 hours = 20 worker-hours

Each vehicle requires 1 worker-hour

For five workers it will take four hours

amid [387]3 years ago
3 0
ANSWER: 4 hours.
As the number of employees who do the same work increase, the number of hours to finish is shorter
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In right triangle ABC, the measure of angle A is 25 degrees, angle c is 90 degrees, and AB = 1. what is the length of AC?
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Answer:

b= 0.9

Step-by-step explanation:

first you find angle B: 180-90-25=65

then you will do law of sine- sin A/a=sin B/b=sin C/c

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sin(90)*b=sin(65)*1

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3 years ago
ABCD Is a rectangle that represents a park.
Andru [333]

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = \sqrt{50^{2}+80^{2} } = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = \frac{15}{2} = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = \frac{47.123}{2} = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.

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