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kenny6666 [7]
3 years ago
6

Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep

the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate View Available Hint(s) Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate four times as fast. at the same rate. one-fourth as fast. twice as fast. one-half as fast.
Physics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

w = w₀ / 2    the angular velocity is half the initial value.

Explanation:

We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved

initial instant.

          L₀ = I₀ w₀

final moment

          L_f = I w

the moment is preserved

          L₀ = L_f

          I₀ w₀ = I w

the moment of inertia of a disk is

         I = ½ m R²

we substitute

          ½ m R² w₀ = ½ (2m) R² w

          w = w₀ / 2

for the case of a disk with twice the mass, the angular velocity is half the initial value.

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Nervous tissue makes up most of the
LiRa [457]

Answer:

, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.

8 0
3 years ago
A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force
SVEN [57.7K]
Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
velocity (v) =  \frac{distance}{time}

                         = \frac{100~ m}{10~seconds}

                         = 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that, 
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
acceleration (a)= \frac{change~in~velocity}{time}

                               = \frac{v-u}{t}

                               = \frac{10-0}{10}

                               = 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
                = 1200 kg * 1 m/s²
                = 1200 kg.m/s²
                = 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is                                                                                                      same as distance.
</span><span>                          = 1200 N * 100 m
</span>                          = 120000 N.m
                          = 120000 J
Now,
Power (P) = \frac{Work~done(W)}{time(t)}

                 = \frac{120000~J}{10s}

                 = 12000 J/s
                 = 12000 watt
SO,
 A) The acceleration of the car is 1 m/s².
 B) 1200 Newton (N) force must have acted on the car.
 C) The velocity of the car after 10 seconds is 10 m/s.
 D) 120000 Joule (J) work was done on the car.
 E) The engine produced a minimum power of 12000 watt.
5 0
4 years ago
What has more momentum a large truck stopped at a stop sign or a motorcycle moving down the road.
Alona [7]
<h2>I'm pretty sure it's</h2><h2>"<u>a motorcycle moving down the road.</u>"</h2><h3></h3><h3>The truck isn't moving so the truck cannot have momentum.</h3><h3>Momentum is basically "mass in motion."</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
4 0
3 years ago
Calculate the specific heat capacity of a piece of wood if 150.0g of the wood absorbs 67,000 joules of heat, and it’s temperatur
svet-max [94.6K]

Answer:

17.8 J/g^{\circ}C

Explanation:

When a certain amount of substance is supplied with a certain amount of energy Q, the temperature of the substance increases according to the equation

Q=mC\Delta T

where

m is the mass of the substance

C is the specific heat capacity

\Delta T is the change in temperature

In this problem:

m = 150.0 g is the mass of wood

Q=67,000 J is the amount of energy supplied to the wood

\Delta T=55-30=25^{\circ}C is the increase in temperature of the substance

Therefore, the specific heat capacity is:

C=\frac{Q}{m\Delta T}=\frac{67,000}{(150.0)(25)}=17.8 J/g^{\circ}C

5 0
3 years ago
10. The following are the statements regarding the human
irga5000 [103]
I would say D - all p, q, r, and s are true.
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3 years ago
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