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3 years ago

How to be good at rocket league

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

you can look up codes for training packs and go from there

Explanation:

also try to get better boost mangement by picking up the little boost pads also watch pros play

kodGreya [7K]3 years ago

6 0

Answer:

go to like the play ground area, and start off by practicing kicking the ball and getting the buttons on the controller down. watch some yt videos too, they will help out!!

Explanation:

hope this helped :))

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If the half-life of niobium-91 is 680 years, how long will it take for the decay described in the previous question?

Svet_ta [14]

2040

15.4+2.2/2 until it equals 2.2
( divide by 3)

680(years)*3 devisions = 2040

3 0

3 years ago

Read 2 more answers

Pa help po science po yan pang grade 7

AveGali [126]

Answer:

table 1:

1. 100/15 = 6.7 m/s

2. 100/12 = 8.3 m/s

3. 100/9 = 11.1 m/s

table 2:

1. 100/8 = 12.5 m/s

2. 100/6 = 16.7 m/s

3. 100/4 = 25 m/s

Explanation:

8 0

3 years ago

The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371

arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

$q=m\times c\times (T_2-T_1)$

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = $4.18J/g.K$

$T_1$ = initial temperature of water = 293.0 K

$T_2$ = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

$q=250g\times 4.18J/g.K\times (371.2-293.0)K$

$q=81719J$

Now we have to calculate the enthalpy of combustion of octane.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

$\Delta H=\frac{-81719J}{0.015mole}$

$\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol$

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0

3 years ago

Determine the mass of a sphere with a radius of 8 cm having a density of 7500 kg / m3

Aliun [14]

Answer:

Explanation:

V=2140CM3

M=VOLUME*DENSITY

7500kg/m3=7.5g/cm3

2140cm3*7.5g/cm3=16050

16050g

7 0

2 years ago

A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed

Ronch [10]

Answer:5.7m/s

Explanation:

Mass=1kg

Initial velocity=u=8m/s

height=h=1.6m

Final velocity =v

Acceleration due to gravity=g=9.8m/s^2

v^2=u^2-2xgxh

v^2=8^2-2x9.8x1.6

v^2=8x8-2x9.8x1.6

v^2=64-31.36

v^2=32.64

Take the square root of both sides

√(v^2)=√(32.64)

v=5.7

Speed at the height of 1.6m is 5.7m/s

8 0

3 years ago