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olganol [36]
3 years ago
12

PLEASE HELP PLEASEEEE

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

The domain and simplified terms are marked below

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Round to the nearest tenth place it is repeating decimal 4/6
Scilla [17]

Answer:

0.7

Step-by-step explanation:

I divided 4 by 6

0.6666666666666...

Simplify to 0.7

8 0
3 years ago
Solve each inequality. Justify each step (y-) - 4 + 2y > 11
Anna11 [10]
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
4 0
3 years ago
Consider the equation 2y - 4x = 12
Aleks [24]

Answer:

y = 2x + 6 and 2y-4x=12 are the same line, so have infinitely many solutions.

Step-by-step explanation:

2y - 4x = 12

This is the same as y = 2x + 6

4 0
3 years ago
Read 2 more answers
Put in order from least to greatest 65, 34, -50, 28, -64, -45​
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-64, -50, -45, 28, 34, 65
7 0
3 years ago
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Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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